Answer:
The speed of the banana just before it hits the water is:
√(2 · g · h) = v
Explanation:
Hi there!
Before Emily throws the banana, its potential energy is:
PE = m · g · h
Where:
PE = potential energy.
m = mass of the banana.
g = acceleration of the banana due to gravity.
h = height of the bridge (distance from the bridge to the ground).
When the banana reaches the water, all its potential energy will have converted to kinetic energy. The equation for kinetic energy is as follows:
KE = 1/2 · m · v²
Where:
KE = kinetic energy.
m = mass of the banana.
v = speed.
Then, when the banana hits the water:
m · g · h = 1/2 · m · v²
multiply by 2 and divide by m both sides of the equation:
2 · g · h = v²
√(2 · g · h) = v
So first Identify all the given Varibales so u can choose which Eqauton to use
D=200m
T=4s
Vi=10m/s
Vf=?
You should this equation
D= 0.50(Vf+Vi)T
Plug in the values
200= 0.50 (Vf+10) 4
Divide the 4 out of the right side and if you do sumthing to one side you gotta do it to the other
200 divided by 4= 0.50(Vf+10)
50= 0.50(Vf+10)
Now expand the 0.50
So 50= 0.5Vf + 5 (because 0.5 times 10 is 5)
Now get rid of the 5
50-5= 0.5Vf
45 =0.5Vf now Divide the 0.5 out
45 divided by 0.5 = Vf
And 45/0.5 is 90
So 90=Vf
Therefore the final Velocity is 90m/s
Answer:
0.0s
Explanation:
I got it right in acellus
Answer:
Charge, 
Explanation:
It is given that,
The number of electron in a RBCs, 
We need to find the total charge of these electrons in the red blood cell. Let it is q. Using the quantization of charge as follows :
q = ne
e is the change on electron
So, the net charge is 
.
