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dsp73
3 years ago
11

a model rocket climbs 200 m in 4 seconds. if was moving 10 m/s to begin with, what is it’s final velocity?

Physics
1 answer:
artcher [175]3 years ago
8 0
So first Identify all the given Varibales so u can choose which Eqauton to use

D=200m
T=4s
Vi=10m/s
Vf=?

You should this equation

D= 0.50(Vf+Vi)T

Plug in the values

200= 0.50 (Vf+10) 4

Divide the 4 out of the right side and if you do sumthing to one side you gotta do it to the other

200 divided by 4= 0.50(Vf+10)
50= 0.50(Vf+10)

Now expand the 0.50

So 50= 0.5Vf + 5 (because 0.5 times 10 is 5)

Now get rid of the 5

50-5= 0.5Vf

45 =0.5Vf now Divide the 0.5 out

45 divided by 0.5 = Vf

And 45/0.5 is 90

So 90=Vf

Therefore the final Velocity is 90m/s
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Explanation:

What happens to the density of an object if the object is cut in half? ... The density remains the same because cutting the object in half will divide the mass & volume by the same amount. Also, the density of a substance remains the same no matter what size it is.

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Now;

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v = gt

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