Answer:
(D) the sphere
Explanation:
The bodies given are Disk and Solid sphere (uniform sphere)
Moment of inertia of the bodies are
I(disk) = 
I(sphere) = 
Since the moment of inertia of sphere is less than that of disk, therefore sphere will reach the bottom first.
Answer:
Explanation:
We shall apply Ampere's circuital law to find out magnetic field . It is given as follows.
∫B.dl = μ₀ I , B is magnetic field , I is current , μ₀ is permeability .
Radius of the wire r = 1.2 x 10⁻³ m
magnetic field B will be circular in shape around the wire. If B is uniform
∫B.dl = B x 2πr
B x 2πr = μ₀ I
B = μ₀ I / 2πr
= 4π x 10⁻⁷ x 37 /2πx1.2 x 10⁻³
= 10⁻⁷ x 2x37 / 1.2 x 10⁻³
= 61.67 x 10⁻⁴ T
= 62 x 10⁻⁴ T
There are only two things you can do to increase the work output of a machine:
1). Increase the work INput to the machine.
2). Make the machine more efficient ... do things like lubricating it better to eliminate some internal friction.
Answer:
a) x = 4.33 m
, b) w = 2 rad / s
, f = 0.318 Hz
, c) a = - 17.31 cm / s²,
d) T = 3.15 s, e) A = 5.0 cm
Explanation:
In this exercise on simple harmonic motion we are given the expression for motion
x = 5 cos (2t + π / 6)
they ask us for t = 0
a) the position of the particle
x = 5 cos (π / 6)
x = 4.33 m
remember angles are in radians
b) The general form of the equation is
x = A cos (w t + Ф)
when comparing the two equations
w = 2 rad / s
angular velocity and frequency are related
w = 2π f
f = w / 2π
f = 2 / 2pi
f = 0.318 Hz
c) the acceleration is defined by
a == d²x / dt²
a = - A w² cos (wt + Ф)
for t = 0
, we substitute
a = - 5,0 2² cos (π / 6)
a = - 17.31 cm / s²
d) El period is
T = 1/f
T= 1/0.318
T = 3.15 s
e) the amplitude
A = 5.0 cm
