Question

A red blood cell contains 4.8 107 free electrons. What is the total charge of these electrons in the red blood cell?

Answer 1

Answer:

Charge, $q=7.68\times 10^{-12}\ C$

Explanation:

It is given that,

The number of electron in a RBCs, $n=4.8\times 10^7$

We need to find the total charge of these electrons in the red blood cell. Let it is q. Using the quantization of charge as follows :

q = ne

e is the change on electron

$q=4.8\times 10^7\times 1.6\times 10^{-19}\\\\q=7.68\times 10^{-12}\ C$

So, the net charge is $7.68\times 10^{-12}\ C$.