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2 years ago

If a person has the genotype Rr for hair where red is dominant to blue, what phenotype would this person have?

Physics

1 answer:

JulijaS [17]2 years ago

4 0

the person's phenotype would be red hair. phenotype is what you see on the outside, genotype is what the dna says. <3

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Susie blows up a balloon. First, she places the balloon in a bucket of ice water. She observes the balloon. She then removes the

Alexus [3.1K]

For number one she is going to observe the contraction of the ballon

For number two she is going to observe the expansion of the ballon

6 0

2 years ago

During a solar eclipse, the Moon is positioned directly between Earth and the Sun. Find the magnitude of the net gravitational f

dezoksy [38]

Answer:

$F= 2.3733 x10^{20} N$

Explanation:

Let's define the variables to proceed with the operations,

So,

The masses

$M_ {sun} = 1.99 * 10^{30} Kg$

$M_ {Earth} = 5.98 * 10 ^ {24} Kg$

$M_ {Moon} = 7.36 * 10 ^{22} Kg$

Average distances

$\bar {x} _ {Sun \rightarrow Earth} = 1.5 * 10 ^ {11} m$

$\bar {x} _ {Earth \rightarrow Moon} = 3.84 * 10 ^ 8m$

Gravitational constant

$G = 6.67 * 10^ {-11} \frac {Nm ^ 2} {kg ^ 2}$

The formula of the Gravitational Force between the Moon and the Earth would be,

$F = \frac {GM_ {Earth} M_ {Moon}} {(\bar {x} _ {Earth \rightarrow Moon}) ^ 2}$

$F= \frac{(6.67*10^{-11} \frac{Nm^2}{kg^2})(5.98*10^{24}Kg)(7.36*10^{22}Kg)}{(3.84*10^8m)^2}$

$F = 1.9908 * 10 ^{20} N$

This force is in the direction of the earth.

We perform the same process but now between the Sun and the Moon, like this,

$F_2 = \frac {GM_ {Sun} M_ {Moon}} {(\bar {x} _ {Sun \rightarrow Earth} - \bar {x} _ {Earth \rightarrow Moon}) ^ 2}$

$F_2 = \frac{(6.67*10^{-11} \frac{Nm^2}{kg^2})(1.99*10^{30}Kg)(7.36*10^{22}Kg)}{(1.5*10^{11}m-3.84*10^8m)^2}$

$F_2 = 4.3641*10^-{ 20} N$

This force is in the direction of the Sun

The net force must be

$F_ {net} = F_2-F$

$F_ {net} = 2.3733*10^{20} N$

This in the direction of the Sun.

8 0

3 years ago

Help plzzz, if a question has more than one answer, pur both letters! Plzz I need 5 letters, this is the third time I’m posting

Kaylis [27]

Answer:

1) e

2)c

3)b

4)d

i dont know if these are right, but something along these lines if you understand the pattern

Explanation:

4 0

3 years ago

The block A and attached rod have a combined mass of 50 kg and are confined to move along the guide under the action of the 796-

Luba_88 [7]

Answer:

The bending moment is 459.16 N.m

Explanation:

From the given information;

Let's assume that the angle is 66°

Then, the free body diagram is draw and attached in the file below.

Now, the calculation of the acceleration from the first part of the free body diagram is:

$\sum F_x = ma_x \\ \\ 796 - 50(9.81) sin 66=50a \\ \\ 796 - 448.094 = 50 a \\ \\ a = \dfrac{347.906}{50} \\ \\ a = 6.96 \ m/s^2$

Bending moment M:

From the second part of the diagram:

$\sum M_B = mad \\ \\ M - (15 \times 9.81) (1.5) = (25 \times 6.96)(1.5 sin 66) \\ \\ M - 220.725 = 238.435 \\ \\ M = 238.435 + 220.725 \\ \\ \mathbf{M = 459.16 \ N.m}$

6 0

3 years ago

Two long cylinders of radii 5 cm and 10 cm form a coaxial cylindrical capacitor, the space between them being filled with a diel

V125BC [204]

Answer:

Explanation:

8 0

3 years ago