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MrMuchimi
4 years ago
11

Free points im poor so only 9

Physics
2 answers:
mash [69]4 years ago
7 0

Answer:

i feel bad

Explanation:

Reil [10]4 years ago
4 0
I heard free points
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A particular airplane will reach liftoff at a speed of 120 km/h. (a) what minimum constant acceleration does the airplane requir
Sergeu [11.5K]
The working equation for this problem is a derived equation from the rectilinear motion at constant acceleration. The equation is written below:

2ax = v² - v₀²
where
a is the acceleration
x is the distance
v is the final velocity
v₀ is the initial velocity

Of course, the plane starts from rest, so v₀ = 0. The final velocity is the liftoff speed which is v = 120 km/h. Substituting the values:

2a(270 m) = (120 km/h)² - 0²
Solving for a,
a = 26.67 km/h²
4 0
3 years ago
A horizontal force F~ is applied to a block of mass m = 1 kg placed on an inclined
vova2212 [387]

Hi there!

To find the appropriate force needed to keep the block moving at a constant speed, we must use the dynamic friction force since the block would be in motion.

Recall:

\large\boxed{F_D = \mu N}}

The normal force of an object on an inclined plane is equivalent to the vertical component of its weight vector. However, the horizontal force applied contains a vertical component that contributes to this normal force.

\large\boxed{N = Mgcos\theta + Fsin\theta}}

We can plug in the known values to solve for one part of the normal force:

N = (1)(9.8)(cos30)  + F(.5) = 8.49  + .5F

Now, we can plug this into the equation for the dynamic friction force:

Fd= (0.2)(8.49 + .5F) = 1.697 N + .1F

For a block to move with constant speed, the summation of forces must be equivalent to 0 N.

If a HORIZONTAL force is applied to the block, its horizontal component must be EQUIVALENT to the friction force. (∑F = 0 N). Thus:

Fcosθ = 1.697 + .1F

Solve for F:

Fcos(30) - .1F = 1.697

F(cos(30) - .1) = 1.697

F = 2.216 N

6 0
3 years ago
Directions: Name 2 kitchen tools, equipment or materials you are going to
sleet_krkn [62]

Answer:

silverware and tupperware?

7 0
4 years ago
A copper sphere was moving at 25 m/s when it hit another object. this caused all of the ke to be converted into thermal energy f
muminat

ΔT= 81°C  was the increase in temperature.

<h3>steps</h3>

As evidenced by energy conservation

To increase its temperature, all of its kinetic energy will be converted to thermal energy.

\frac{1}{2}mv ^{2} = msΔT

then divide both sides by the object's mass.

\frac{1}{2} v^{2} =sΔT

therefore, a temperature shift is described as

ΔT= V^{2} /2s

ΔT= 25^{2}/ 2 x 387

ΔT= 81°C

ΔT= 81°C  was the increase in temperature.

learn more about increase in temperature here

<u>brainly.com/question/14319779</u>

#SPJ4

3 0
1 year ago
Choose the best description of the attraction between you and your classmate.
Lerok [7]

Answer:

The correct option is;

D. There is not enough information to answer this question

Explanation:

The universal gravitational constant = 6.67408 × 10⁻¹¹ 3³/(kg·s²)

For an in between distance of 1 m and equal masses of 60 kg, we have;

F = G \times \dfrac{m_{1}  \times m_{2}}{r^{2}} = 6.67408 \times 10^{-11}  \times \dfrac{60 \times 60}{1^{2}}  \approx  2.403 \times 10^{-7} N

The gravitational attraction ≈ 2.403 × 10⁻⁷ N, which does not correspond with the answers, therefore, the best option is that there is not enough information to answer this question.

5 0
3 years ago
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