The working equation for this problem is a derived equation from the rectilinear motion at constant acceleration. The equation is written below:
2ax = v² - v₀²
where
a is the acceleration
x is the distance
v is the final velocity
v₀ is the initial velocity
Of course, the plane starts from rest, so v₀ = 0. The final velocity is the liftoff speed which is v = 120 km/h. Substituting the values:
2a(270 m) = (120 km/h)² - 0²
Solving for a,
a = 26.67 km/h²
Hi there!
To find the appropriate force needed to keep the block moving at a constant speed, we must use the dynamic friction force since the block would be in motion.
Recall:

The normal force of an object on an inclined plane is equivalent to the vertical component of its weight vector. However, the horizontal force applied contains a vertical component that contributes to this normal force.

We can plug in the known values to solve for one part of the normal force:
N = (1)(9.8)(cos30) + F(.5) = 8.49 + .5F
Now, we can plug this into the equation for the dynamic friction force:
Fd= (0.2)(8.49 + .5F) = 1.697 N + .1F
For a block to move with constant speed, the summation of forces must be equivalent to 0 N.
If a HORIZONTAL force is applied to the block, its horizontal component must be EQUIVALENT to the friction force. (∑F = 0 N). Thus:
Fcosθ = 1.697 + .1F
Solve for F:
Fcos(30) - .1F = 1.697
F(cos(30) - .1) = 1.697
F = 2.216 N
Answer:
silverware and tupperware?
ΔT= 81°C was the increase in temperature.
<h3>
steps</h3>
As evidenced by energy conservation
To increase its temperature, all of its kinetic energy will be converted to thermal energy.
ΔT
then divide both sides by the object's mass.
ΔT
therefore, a temperature shift is described as
ΔT= 
ΔT=
/ 2 x 387
ΔT= 81°C
ΔT= 81°C was the increase in temperature.
learn more about increase in temperature here
<u>brainly.com/question/14319779</u>
#SPJ4
Answer:
The correct option is;
D. There is not enough information to answer this question
Explanation:
The universal gravitational constant = 6.67408 × 10⁻¹¹ 3³/(kg·s²)
For an in between distance of 1 m and equal masses of 60 kg, we have;

The gravitational attraction ≈ 2.403 × 10⁻⁷ N, which does not correspond with the answers, therefore, the best option is that there is not enough information to answer this question.