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slega [8]
3 years ago
9

This season, the probability that the Yankees will win a game is 0.61 and the

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0

The probability that the Yankees will lose when they score fewer than 5 runs is 17.16%.

<h3><u>Probability </u></h3>

Given that this season, the probability that the Yankees will win a game is 0.61 and the probability that the Yankees will score 5 or more runs in a game is 0.56, and the probability that the Yankees win and score 5 or more runs is 0.44, to determine what is the probability that the Yankees will lose when they score fewer than 5 runs the following calculation must be made:

  • 1 - 0.61 = 0.39
  • 1 - 0.56 = 0.44
  • 0.39 x 0.44 = X
  • 0.1716 = X

Therefore, the probability that the Yankees will lose when they score fewer than 5 runs is 17.16%.

Learn more about probability in brainly.com/question/11234923

#SPJ1

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Sophia drives to work every day from Monday-friday. Sophias work is 28km away from her house.
expeople1 [14]

Answer:

56

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Step-by-step explanation:

5 0
3 years ago
A school survey found that 7 out of 30 students walk to
nika2105 [10]

Answer: 7/145

Step-by-step explanation:

The probability that the first student walks to school will be: = 7/30.

The probability of selecting the second student that walks to school will be: = 6/29.

Then we multiply both together and this will be:

= 7/30 × 6/29

= 7/145

5 0
4 years ago
A Travel Weekly International Air Transport Association survey asked business travelers about the purpose for their most recent
siniylev [52]

Answer:

(a) P (p' > 0.25) = 0.

(b) P (0.15 < p' < 0.20) = 0.7784.

(c) P (133 < X < 171) = 0.2205

Step-by-step explanation:

Let <em>p</em> = proportion of business trip that were for  internal company visit.

It is provided that 19% responded that it was for an internal company visit, i.e.

<em>p</em> = 0.19.

A sample of <em>n</em> = 950 business travelers are randomly selected.

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

Thus, the distribution of \hat p is N (<em>μ</em> = 0.19, <em>σ </em>= 0.013).

(a)

Compute the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit as follows:

P (p' > 0.25) = P (Z > 4.62) = 0

*Use a <em>z</em>-table for the probability.

Thus, the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.

(b)

Compute the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit as follows:

P (0.15 < p' < 0.20) = P (-3.08 < Z < 0.77)

                               = P (Z < 0.77) - P (Z < -3.08)

                               = 0.7794 - 0.0010

                               = 0.7784

*Use a <em>z</em>-table for the probability.

Thus, the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.7784.

(c)

Compute the proportion of <em>X</em> = 133  and <em>X</em> = 171 as follows:

p' = 133/950 = 0.14

p' = 171/950 = 0.18

Compute the value of P (0.14 < p' < 0.20) as follows:

P (0.14 < p' < 0.18) = P (-3.85< Z < -0.77)

                               = P (Z < -0.77) - P (Z < -3.85)

                               = 0.2206- 0.0001

                               = 0.2205

*Use a <em>z</em>-table for the probability.

Thus, the probability that between 133 and 171 of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.2205.

7 0
4 years ago
What is the value of y?<br> O A. 30°<br> OB. 40°<br> O C. 50°<br> O D. 60°
Lera25 [3.4K]
<h3>Answer:  B. 40</h3>

For any triangle, the three angles always add to 180

(y+10)+(2y)+(50) = 180

3y+60 = 180 ... combine like terms

3y+60-60 = 180-60 ... subtract 60 from both sides

3y = 120

3y/3 = 120/3 .... divide both sides by 3

y = 40

5 0
3 years ago
PLEASE HELP!!!
Sliva [168]
Since the number of green and blue marbles is the same, and the number of green marbles is divisible by 8, and the blue marbles by 6, the number of green marbles (and of the blue marbles) must be a multiple of both 6 and 8. The least common multiple of 6 and 8 is 24. So there can be either 24 blue and 24 green marbles, leaving 52 for red and yellow, or 48 blue and 48 green marbles, leaving 2 for red and yellow.

Since red and yellow are the same number, there could be either 26 yellow, or 1 yellow. Since 1 isn't given as an option, it has to be C) 26.
3 0
3 years ago
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