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kondor19780726 [428]
2 years ago
8

the graph at left in the tctct, c-plane models the global wind power capacity, ccc, in gigawatts, ttt years since 199619961996.

what is the best interpretation of the ccc-intercept of this graph?
Computers and Technology
1 answer:
Elena-2011 [213]2 years ago
4 0

The intercept of a graph is the point where the graph crosses the axes of the graph.

The interpretation of the c-intercept is: <em>in 1996, the global wind power capacity was approximately 7 gigawatts.</em>

On the graph (see attachment), we have the following observations

  1. The vertical axis represents the global wind power capacity (i.e. the c-axis)
  2. The horizontal axis represents the years since 1996 (i.e. the t-axis)

So, the c-intercept is the point that crosses the vertical axis.

From the graph, the curve crosses the c-axis at c = 7, and t = 0 (i.e. years = 1996)

Hence, the interpretation of the c-intercept is: <em>in 1996, the global wind power capacity was approximately 7 gigawatts.</em>

<em />

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Read more about intercepts at:

brainly.com/question/3334417

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If a user's input string matches a known text message abbreviation, output the unabbreviated form, else output: Unknown. Support
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Here is the JAVA program. I  have added a few more abbreviations apart from LOL and IDK.

import java.util.Scanner; // to take input from user

public class MessageAbbreviation {

public static void main(String[] args) { //start of main() function body

   Scanner input = new Scanner(System.in); // create object of Scanner

       String abbreviation= ""; //stores the text message abbreviation

/* In the following lines the abbreviation string type variables contain the un-abbreviated forms */

           String LOL = "laughing out loud";

           String IDK = "i don't know";

           String BFF = "best friends forever";

           String IMHO = "in my humble opinion";

           String TMI = "too much information";

           String TYT = "take your time";

           String IDC = "I don't care";

           String FYI = "for your information";

           String BTW = "by the way";

           String OMG = "oh my God";

//prompts the user to enter an abbreviation for example LOL

           System.out.println("Input an abbreviation:" + " ");

           if(input.hasNext()) { // reads the abbreviation form the user

           abbreviation= input.next(); }

// scans and reads the abbreviation from user in the abbreviation variable

/*switch statement checks the input abbreviation with the cases and prints the un abbreviated form in output accordingly. */

    switch(abbreviation) {

       case "LOL" : System.out.println(LOL);

                    break;

       case "IDK" : System.out.println(IDK);

                    break;

       case "BFF" : System.out.println(BFF);

                    break;

       case "IMHO": System.out.println(IMHO);

                     break;

       case "TMI": System.out.println(TMI);

                     break;

       case "TYT": System.out.println(TYT);

                     break;

       case "IDC": System.out.println(IDC);

                     break;

       case "FYI": System.out.println(FYI);

                     break;

       case "BTW": System.out.println(BTW);

                     break;

       case "OMG": System.out.println(OMG);

                     break;

                     

       default    : System.out.println("Unknown"); } } }

Explanation:

The program first prompts the user to enter an abbreviation. Lets say the user enters LOL. Now the switch statement has some cases which are the conditions that are checked against the input abbreviation. For example if the user enters LOL then the following statement is executed:

case "LOL" : System.out.println(LOL);

This means if the case is LOL then the message ( un abbreviated form) stored in the LOL variable is displayed on output screen So the output is laughing out loud.

Anything else entered other than the given abbreviations will display the message: Unknown

The output is attached as screen shot.

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