Answer:
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Explanation:
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Answer:
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Explanation:
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Answer:
informative, discrimiitive,critical thats the order
Using the knowledge in computational language in C++ it is possible to write a code that Find the Average of the sum of prime numbers between 1 to any given number
<h3>Writting in C++ code:</h3>
<em />
<em>#include <iostream></em>
<em>using namespace std;</em>
<em>bool isPrime(int n){</em>
<em> for(int i = 2; i < n/2; i++){</em>
<em> if(n%i == 0){</em>
<em> return false;</em>
<em> }</em>
<em> }</em>
<em> return true;</em>
<em>}</em>
<em>int findPrimeSum(int n){</em>
<em> int sumVal = 0;</em>
<em> for(float i = 2; i <= n; i++){</em>
<em> if(isPrime(i))</em>
<em> sumVal += i;</em>
<em> }</em>
<em> return sumVal;</em>
<em>}</em>
<em>int main(){</em>
<em> int n = 15;</em>
<em> cout<<"The sum of prime number between 1 to "<<n<<" is "<<findPrimeSum(n);</em>
<em> return 0;</em>
<em>}</em>
See more about C++ code at brainly.com/question/19705654
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Explanation:
Explanation:They are
Explanation:They are 1) start the process
Explanation:They are 1) start the process 2) Input N, the number for which multiplication table is to be printed
Explanation:They are 1) start the process 2) Input N, the number for which multiplication table is to be printed 3) For T = 1 to 10
Explanation:They are 1) start the process 2) Input N, the number for which multiplication table is to be printed 3) For T = 1 to 104) print M = N*T
Explanation:They are 1) start the process 2) Input N, the number for which multiplication table is to be printed 3) For T = 1 to 104) print M = N*T5) End for
Explanation:They are 1) start the process 2) Input N, the number for which multiplication table is to be printed 3) For T = 1 to 104) print M = N*T5) End for6) Stop the process