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Using Lagrange multipliers, we have the Lagrangian
with partial derivatives (set equal to 0)
Substituting the first three equations into the fourth allows us to solve for
:
For each possible value of, we get two corresponding critical points at 
.
At these points, respectively, we get a maximum value of
and a minimum value of 
.
with partial derivatives (set equal to 0)
Substituting the first three equations into the fourth allows us to solve for
For each possible value of
At these points, respectively, we get a maximum value of
Answer and explanation:
Given : A driving exam consists of 29 multiple-choice questions. Each of the 29 answers is either right or wrong. Suppose the probability that a student makes fewer than 6 mistakes on the exam is 0.26 and that the probability that a student makes from 6 to 20 (inclusive) mistakes is 0.53.
Let X be the number of mistake
To find : The probability of each of the following outcomes.
a) A student makes more than 20 mistakes
i.e.
b. A student makes 6 or more mistakes
i.e.
c. A student makes at most 20 mistakes
i.e.
Using 'a' part
d. Which two of these three events are complementary?
The complement of an event happening is the exact opposite: the probability of it not happening.
According to definition,
Option a and c are complementary events.