The volume of the sphere is expressed in the formula V = 4/3 pi r^3. The rate of change of volume is determined by differentiating the formula: dV/dt = 4pi r^2 dr/dt. When we substitute 500 cm3/min as dV/dt and 30 cm as r. Then dr/dt is equal to 0.0442 cm/min
Answer: The Fuschia Bot clicks _6_ times in 0.75 sec,
Step-by-step explanation:
Multiply the unit rate by time:
.75 sec × 8 clicks/sec
Seconds cancel. .75(8) = 6 clicks
Answer:
The probability is 1/2
Step-by-step explanation:
The time a person is given corresponds to a uniform distribution with values between 0 and 100. The mean of this distribution is 0+100/2 = 50 and the variance is (100-0)²/12 = 833.3.
When we take 100 players we are taking 100 independent samples from this same random variable. The mean sample, lets call it X, has equal mean but the variance is equal to the variance divided by the length of the sample, hence it is 833.3/100 = 8.333.
As a consecuence of the Central Limit Theorem, the mean sample (taken from independant identically distributed random variables) has distribution Normal with parameters μ = 50, σ= 8.333. We take the standarization of X, calling it W, whose distribution is Normal Standard, in other words

The values of the cummulative distribution of the Standard Normal distribution, lets denote it
, are tabulated and they can be found in the attached file, We want to know when X is above 50, we can solve that by using the standarization

Answer:
A: 6 triangles with height 10.4 inches each and base 12 inche
B: 62.4 square inches
C: 374.4 square inches
Step-by-step explanation:
Part A: You can form a triangle by connecting E to the top of the segment and connecting the top of the segment to D. Recreating this with each section will create 6 triangles with height 10.4 inches each and base 12 inches.
Part B: The area of a triangle is A = 1/2b*h. Substitute h = 10.4 and b = 12.
A = 1/2*10.4*12 = 62.4
Part C: There are 6 triangles each with area 62.4. So the area of the whole figure will be 6*62.4 = 374.4.
If you list all the common factors, (1,2,3,6), you see the highest common factor is 6