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Ivanshal [37]
3 years ago
5

If a car goes around a turn too quickly, it can leave tracks that form an arc of a circle. By finding the radius of the circle,

accident investigators can estimate the speed of the car. To find the radius, accident investigators choose points A and B on the tire marks. Then, the investigators find the midpoint C of AB¯¯¯¯¯¯¯¯. Use the diagram to find the radius r of the circle. Round your answer to the nearest tenth.

Mathematics
2 answers:
liubo4ka [24]3 years ago
8 0
Given:
Segment AC = 130 feet
Segment CD = 70 feet

I think that I'll be using the Pythagorean Theorem in finding the value of r. r will be the hypotenuse

Segment CE = (r - 70 feet)

r² = a² + b²
r² = 130² + (r-70)²
r² = 16,900 + (r-70)(r-70)
r² = 16,900 + r² - 70r - 70r + 4900
r² - r² + 140r = 16,900 + 4,900
140r = 21,800
r = 21,800/140
r = 155.71 feet

The radius of the circle is 155.71 feet.

Otrada [13]3 years ago
3 0

Answer: 155.7

Step-by-step explanation:

Use what you know.

Segment AC is 130 ft

Segment CD is 70ft

If you use the Pythagorean Theorem, in this case being r^{2} = a^{2} + b^{2}

To find segment CE, you would do r-70

So, r^{2} = 130^{2} + (r-70)^{2}

r^{2} = 16,900 + r^{2} -140r + 4900

Add the -140r to the left side and then get rid of the two r^{2}. Then Add 16,900 and 4900 together

You'll end up with 140r = 21,800

Divide 140 on each side.

Your final answer will be 155.7 (rounded to the nearest tenth)

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8 0
3 years ago
A family has two cars. The first car has a fuel efficuency of 15 miles per gallon of gas and the second has a fuel efficiency of
SVEN [57.7K]

Answer:

x= 35 gallons consumed by 1st car

and y= 40  gallons consumed by 2nd car

Step-by-step explanation:

Fuel efficiency of 1st car = 15 miles per gallon

Fuel efficiency of 2nd car = 35 miles per gallon

Let x= gallons consumed by 1st car

and y= gallons consumed by 2nd car

Total gallons consumed by both cars = 75

so, we can write

x + y = 75

Miles covered by both cars = 1925 miles

and we know, Fuel efficiency of 1st car = 15 miles per gallon

Fuel efficiency of 2nd car = 35 miles per gallon

we can write the equation as

15 x + 35 y = 1925

where x and y are gallons consumed by 1st and 2nd car.

We have two equation now,

x + y = 75                   (1)

15 x + 35 y = 1925     (2)

Multiplying eq(1) with 15 and subtracting eq (1) and 2

15 x + 15 y = 1125

15 x + 35 y = 1925

-       -            -

_______________

0 - 20 y = -800

y= -800 / -20

y = 40

Putting value of y in equation 1

x + y = 75

x + 40 = 75

x= 75 - 40

x = 35

x= 35 gallons consumed by 1st car

and y= 40  gallons consumed by 2nd car

4 0
3 years ago
V= 2i +9j Find ||9v||
Korvikt [17]

Answer:

9\sqrt{85}

Step-by-step explanation:

9v = 9(2i + 9j) = 18i + 81j

|9v | = \sqrt{18^2+81^2} = \sqrt{x6885} = 9\sqrt{85}


8 0
3 years ago
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