Answer:
MnSO₄.7H₂O
Explanation:
To solve this question, we need to convert the mass of the dehydrated MnSO₄. The difference between mass of the hydrate and dehydrated compound is the mass of water. With the mass we can find the moles of water and the formula of the hydrate:
<em>Moles MnSO₄ -Molar mass: 151g/mol-:</em>
17.51g * (1mol / 151g) = 0.116 moles
<em>Moles H₂O -Molar mass: 18g/mol-:</em>
32.14g-17.51g = 14.63g * (1mol / 18g) = 0.813 moles
The ratio of moles MnSO₄: Moles H₂O represent the amount of water molecules in the hydrate:
0.813mol / 0.116mol = 7 molecules of water.
The hydrate formula is:
<h3>MnSO₄.7H₂O</h3>
<span>sudden increase of Nitrate and Phosphate in March to April that occurred, it causes the fish tank to produce algae</span>
Answer:
11.99
% ≅ 12.0%.
Explanation:
∵ mass % = [mass of solute/mass of solution] x 100.
mass of solute (CaCl₂) = 8.87 g & mass of solution = 8.87 g + 65.1 g = 73.97 g.
<em>∴ mass % of (CaCl₂) = [mass of solute/mass of solution] x 100 </em>= (
8.87 g/ 73.97 g) x 100 = <em>11.99
% ≅ 12.0%.</em>
The wrong answers for sure are B and D, I assume the answer is C
