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Airida [17]
3 years ago
10

What are some 6th grade math

Mathematics
2 answers:
IgorLugansk [536]3 years ago
6 0
A^2+b^2=c^2 that is a formula
Vedmedyk [2.9K]3 years ago
5 0

Step-by-step explanation:

Algebra

Common Core

Per Algebra

Fractions and Decimals

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-3-(-2)+(-10)<br><br> Explain answer
natka813 [3]

Answer:

-11

Step-by-step explanation:

-3-(-2)+(-10)

Two - make a pos -3+2+(-10)

-1+(-10)

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3 years ago
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Graph the system of equations. {x−y=64x+y=4
Fantom [35]
X-y=6 Equation 1
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To graph the given system of equation, first find x and y-intercept of each equation.
x-y=6
When y=0
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When x=0
-y=6
y=-6  Point is (0,-6)

Now x-intercept and y-intercept for equation 2.
x+y=4
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Now plot these points on the graph, the lines intersect each other at point (5,-1), which is the solution of the given system.

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3 years ago
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3 years ago
use the poisson distribution to find the indicated probability. if the random variable x has a poisson distribution with mean of
Hitman42 [59]
P(X=2)=\frac{e^{-6} 6^{2}}{2}=0.045
4 0
3 years ago
I need help w/ this!! thank you
Fittoniya [83]
<h3><u>Answer:</u></h3>

\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}

<h3><u>Step-by-step explanation:</u></h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2  \\\\\bf\implies (2y+3)^2 \leq 1  \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1  \\\\\bf\implies 4y^2+9+12y - 1 \leq 0  \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0  \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup   \\\\\bf\implies y^2y+2y+y+2 \leq 0  \\\\\bf\implies y(y+2)+1(y+2)\leq 0  \\\\\bf\implies ( y+2)(y+1)\leq 0  \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}

<h3><u>Hence</u><u> the</u><u> </u><u>standa</u><u>rd</u><u> </u><u>form</u><u> </u><u>of</u><u> </u><u>inequa</u><u>lity</u><u> </u><u>is</u><u> </u><u>y²</u><u>+</u><u>3y</u><u> </u><u>+</u><u>2</u><u> </u><u>≤</u><u> </u><u>0</u><u> </u><u>and</u><u> </u><u>the </u><u>Solution</u><u> </u><u>set</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ineq</u><u>uality</u><u> </u><u>is</u><u> </u><u>[</u><u> </u><u>-</u><u>2</u><u> </u><u>,</u><u> </u><u>-</u><u>1</u><u> </u><u>]</u><u> </u><u>.</u></h3>
4 0
2 years ago
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