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sesenic [268]
4 years ago
7

Scientific endeavor should only be pursued after known tradeoffs associated with the research have been considered.

Physics
1 answer:
hram777 [196]4 years ago
7 0
True because then you know what you're getting into
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4. The Voyager 1 and 2 spacecraft are now out beyond the orbit of Pluto. They have run out of fuel long ago but are still moving
tekilochka [14]

Answer:

C

Explanation:

According to Newton's first law of motion, which states that a body will continue in its state of rest or uniform motion unless acted upon by an external force to change its state of rest or uniform motion. So, the Voyagers spacecraft will continue to move in the same way at the constant speed of 50,000 mph unless acted upon by a force.

7 0
3 years ago
Read 2 more answers
A snail moves 40 cm in<br> 20 seconds. How fast<br> did it move?
nasty-shy [4]

Answer:

too fast to be a snail

......

2 cm per second

5 0
3 years ago
BRAINLIST A wave travels at a constant speed. How does the wavelength change if the
Studentka2010 [4]
I think it will be (c)
3 0
3 years ago
Giving quadrilateral a(2,-1 ) b ( 1,3) c(6,5) d(7,1) you want to prove that it is a parallelogram by showing opposite sides are
solong [7]

Answer:

Opposite sides are congruent (AB = DC).

Opposite angels are congruent (D = B).

Consecutive angles are supplementary (A + D = 180°).

If one angle is right, then all angles are right.

The diagonals of a parallelogram bisect each other.

Each diagonal of a parallelogram separates it into two congruent triangles.

Explanation: #if you need any queshtions answered within secs/mins hit me up and I gotchu.

8 0
3 years ago
What will be the final temperature if a 4.00 g silver ring at 41.0◦C if it gives off 18.0 J of heat to the surroundings? The spe
Eduardwww [97]

Answer:

Final temperature, T_f=21.85^{\circ}

Explanation:

Given that,

Mass of silver ring, m = 4 g

Initial temperature, T_i=41^{\circ}C

Heat released, Q = -18 J (as heat is released)

Specific heat capacity of silver, c=0.235\ J/g\ C

To find,

Final temperature

Solution,

The expression for the specific heat is given by :

Q=mc\Delta T

Q=mc(T_f-T_i)

T_f=\dfrac{-Q}{mc}+T_i

T_f=\dfrac{-18}{4\times 0.235}+41

T_f=21.85^{\circ}

So, the final temperature of silver is 21.85 degrees Celsius.

5 0
3 years ago
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