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SpyIntel [72]
3 years ago
10

Why is it difficult to define psychology disorder

Physics
1 answer:
Thepotemich [5.8K]3 years ago
4 0

One of the contributing factors for the need to define mental disorder was an attempt not to include situations more related to cultural, moral, and religious values than to medical ones (which define what is harmful to the patient and should be treated) and which long undermined psychiatric classifications.

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A Hertzsprung-Russel diagram is shown. Which stars are best characterized as having high temperatures and low luminosities?
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White dwarfs

<u>Explanation:</u>

Hertzsprung-Russel graph is a 2-dimensional graph, plotting star’s luminosity against temperature they emit.

White dwarfs are the star exhibiting high temperatures and low luminosities. These stars are extremely dense and mass comparable to that of the sun.

The main cause of low luminosities in the absence of fusion reaction inside the core of the star. Faint luminosity is provided by the thermal energy of the star. They are considered to be in the final stage of evolution having masses in the range of 10 solar mass (hence not enough to form a star)

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The Graph Shows World Disasters.

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An aluminum wire with a diameter of 0.100mm has a uniform electric field of 0.200V/m imposed along its entire length. The temper
Aleonysh [2.5K]
  1. The linear resistivity of this wire is equal to 3.15 × 10⁻⁸ Ωm.
  2. The current density in this wire is equal to 6.35 × 10⁶ A/m².
  3. The total current in a wire is equal to 0.0499 Amp.
  4. The drift speed of the conduction electrons is equal to 6.59 × 10⁻⁴ m/s.
  5. The potential difference between the ends of this wire is equal to 0.4 Volt.

<u>Given the following data:</u>

Diameter of aluminum wire = 0.100 mm.

Uniform electric field of aluminum wire = 0.200 V/m.

Temperature of aluminum wire = 50.0°C.

<u>Scientific data:</u>

Resistivity of aluminum, ρ = 2.82 × 10⁻⁸ Ωm

Temperature coefficient for aluminum, α = 3.9 × 10⁻³ °C⁻¹.

<h3>How to determine the resistivity?</h3>

Mathematically, the linear resistivity of a material can be calculated by using this formula:

ρ = ρ₀(1 + αΔT)

ρ = ρ₀(1 + α(T₂ - T₁)

ρ = 2.82 × 10⁻⁸ × [1 + 3.9 × 10⁻³(50 - 20)

Resistivity, ρ = 3.15 × 10⁻⁸ Ωm.

<h3>What is the current density in this wire?</h3>

Mathematically, the current density in a wire can be calculated by using this formula:

J = σE = E/ρ

J = 0.2/3.15 × 10⁻⁸

Current density, J = 6.35 × 10⁶ A/m².

<h3>What is the total current in this wire?</h3>

Mathematically, the total current in a wire can be calculated by using this formula:

I = JA = J(πr²)

I = 6.35 × 10⁶ × (3.142 × 0.00005²)

Total current, I = 0.0499 Amp.

<h3>What is the drift speed of the conduction electrons?</h3>

Mathematically, the drift speed of the conduction electrons can be calculated by using this formula:

V = I/nqA

V = (0.0499 × 0.027)/(6.023 × 10²³ × 27000 × 1.602 × 10⁻¹⁹ × (3.142 × 0.00005²)

Drift speed, V = 6.59 × 10⁻⁴ m/s.

For the the potential difference, we have:

Mathematically, the potential difference between the ends of a wire can be calculated by using this formula:

ΔV = El

ΔV = 0.2 × 2

ΔV = 0.4 Volt.

Read more on drift speed here: brainly.com/question/15219891

#SPJ4

Complete Question:

An aluminum wire with a diameter of 0.100 mm has a uniform electric field of 0.200 V/m imposed along its entire length. The temperature of the wire is 50.0°C. Assume one free electron per atom.

(a) Determine the resistivity.

(b) What is the current density in the wire?

(c) What is the total current in the wire?

(d) What is the drift speed of the conduction electrons?

(e) What potential difference must exist between the ends of a 2.00-m length of the wire to produce the stated electric field?

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2 years ago
What would be the effect on the annual march of the seasons if earth's axis were not inclined relative to the plane of the eclip
victus00 [196]
The poles wouldn't get light all year round.
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