Answer:
Explanation:
Let the potential difference between plate be V .
Electrical energy lost for cyberon = V x 3e
Kinetic energy lost by cyberon = kinetic energy gain by it
V x 3e = 1/2 x 3m x vc²
For electron , the above equation becomes
V x e = 1/2 x m x ve²
Dividing the two equations
1 = vc² / ve²
vc = ve .
vc / ve = 1 .
Answer:
Explanation:
The complete question is here.
A spring is compressed between two objects with unequal masses, m and M, held together. The objects are initially at rest on a horizontal friction less surface. When released, which of the following is true?
a) Kinetic energy is same as before being released
b) The total final kinetic energy is zero.
c) The two objects have equal kinetic energy.
d) The speed of one object is equal to the speed of other.
e) The total final momentum of two objects is zero.
So option e) the total final momentum of two objects is zero.
Answer:
<h2>when metallic oxides react with water they form metallic hydroxides which are basic in nature.to show that these are basic in nature,we should conduct a litmus paper test.in this experiment,we will observe that red litmus turns blue on coming in contact with them. this shows that metallic oxides are basic in nature</h2>
Answer: The acceleration will be greater in the kickball than the soccer ball since the kick ball has a smaller mass and provided they are acted upon with equal force magnitude.
Explanation:
We can prove this by substituting with numerical values.
Say the force she kicked both balls with was 30 N. The mass of the soccer ball is 10kg and the mass of the kickball is 6kg.
Applying Newtons Second Law, F = ma
For the soccer ball:
30 = 10a
a = 30/10
a = 3
For the kickball:
30 = 6a
a = 30/6
a = 5
Hence the kickball will travel with a greater acceleration given the same force is acted upon and has a smaller mass than the soccer ball
Hope this helps, brainliest would be appreciated :)
Answer:
F_total = 10000 N
Explanation:
For this exercise we use that the force is a vector and the best way to do the sum is that since the two tugs pull the boat with the same intensity and angle, the sum of the component of the force perpendicular to the movement becomes zero.
The components parallel to the movement of the tugs is
∑ F = 2 Fcos θ
let's calculate
F_total = 2 10000 cos 60
F_total = 10000 N
