Answer:
here I am just giving an idea of how the graph will be like ...
In the pic..
Hope it helped u if yes mark me BRAINLIEST!
Tysm!
:)
Answer:
The velocity of the object at the bottom is, v = 17.15 m/s
Explanation:
Given data,
The initial velocity of the object, u = 0
The height of the hill, h = 15 m
Let 'S' be the distance of the slope of the hill and 'Ф' be the slope of the hill formed with the ground.
The acceleration due to gravity component along the slope is given by,
a = g Sin Ф
The distance of the slope since height 'h' of the hill is given,
s = h / Sin Ф
Using the III equation of motion,
v² = 2 as (∵ u = 0)
v² = 2 x g Sin Ф x h / Sin Ф
= 2 gh
Therefore,
<em> v = √(2gh)</em>
Substituting the given values,
v = √(2x9.8x15)
= 17.15 m/s
Hence, the velocity of the object at the bottom is, v = 17.15 m/s
Ben works as a medical assistant. He needs to take a patient's vitals, but the patient is refusing to cooperate. He hasn't experienced this before, so he decides to ask a nurse for advice on how to handle it. This is making a decision by O a) delegation. O b) command. c) vote. O d) consult. Question
The answer is A.68 degrees
In order to make things easier to describe and explain, let's call
the resistance of each bulb 'R', and the battery voltage 'V'.
a). In series, the total resistance is 3R.
In parallel, the total resistance is R/3.
Changing from series to parallel, the total resistance of the circuit
decreases to 1/9 of its original value.
b). In series, the total current is V / (3R) .
In parallel, the total current is 3V / R .
Changing from series to parallel, the total current in the circuit
increases to 9 times its original value.
c). In series, the power dissipated by the circuit is
(V) · V/3R = V² / 3R .
In parallel, the power dissipated by the circuit is
(V) · 3V/R = 3V² / R .
Changing from series to parallel, the power dissipated by
the circuit (also the power delivered by the battery) increases
to 9 times its original value.
