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pantera1 [17]
3 years ago
12

In 2013 the world consumption of oil was estimated at 3.3 ´ 1010 barrels per year. The world reserves of oil in 2013 were estima

ted as 1.324 ´ 1012 barrels. Estimate how many years the current reserves of oil will last assuming that consumption remains at the 2013 rate.
Chemistry
1 answer:
Serga [27]3 years ago
3 0

Answer:

  about 37 years

Explanation:

If 100% of the estimated reserves are used at the current rate, it will take ...

  (1.234·10^12 bbl)/(3.3·10^10 bbl/yr) = 37.4 yr

It will take about 37 years to deplete the reserves.

__

Your calculator can perform arithmetic using scientific notation.

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How does the size of the atom (atomic size) change as you move from the LEFT side to RIGHT side of the Periodic Table?
Shtirlitz [24]

Answer:

B

Explanation:

As you move from left to right, the number of protons increases. More protons means a bigger positive charge to pull in the electrons from the shells. This would then decrease the size of the atom.

Thus, the answer is B, the size decreases.

Hope this helps!

3 0
4 years ago
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Burning a candle melts the wax, but also burns the wick. Explain how burning a candle involves both physical and chemical change
k0ka [10]

Answer:

Burning of the candle is both physical and chemical change. Burning of the candle melts the wax and hence physical state of wax has changed from solid to liquid.  

Again the wax combines with the atmospheric oxygen and changes to carbon dioxide, heat and light.  

Thus both the changes are accompanied by the burning of the candle.

Explanation:

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3 0
3 years ago
Aqueous potassium bromide reacts with aqueous silver nitrate AgNO3 to form aqueous potassium nitrate KNO3 and solid silver bromi
ddd [48]
The balanced chemical equation for the reaction  is as below

 KBr (aq) + AgNo3  → KNO3(aq)  + AgBr(s)

  Explanation

    from the equation above  the  stoichiometric  coefficient  before KBr is 1,  before  AgNo3  is 1 ,  before KNO3  is 1  and before AgBr is also 1.  Therefore   1 mole of KBr  reacted with  1 mole of AgNO3  to form 1 mole of KNO3  and 1 mole  of AgBr.

8 0
3 years ago
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A certain reaction at equilibrium has more moles of gaseous products than of gaseous reactants.(b) Write a statement about the r
mojhsa [17]

To be equal as K_p , K_c needs to be divided by (RT)^{\Delta n}

<h3>Briefly explained</h3>

When the amount of gaseous reactant is greater than the amount of gaseous product, where n_{products} < n_{reactants},

then = K_p < K_c

It's because \Delta n is negative, which places (RT) in the denominator. This is how the equation will now appear.

K_p = K_c(RT)^{-\Delta n} = \frac{ K_c}{(RT)^{\Delta n}}

Here you can observe the value of K_c  is greater than K_p. To be equal as K_p , K_c needs to be divided by (RT)^{\Delta n}

<h3>What is Δngas?</h3>

The number of moles of gas that move from the reactant side to the product side is denoted by the symbol ∆n or delta n in this equation.

Once more, n represents the growth in the number of gaseous molecules the equilibrium equation can represent. When there are exactly the same number of gaseous molecules in the system, n = 0, Kp = Kc, and both equilibrium constants are dimensionless.

<h3>Definition of equilibrium</h3>

When a chemical reaction does not completely transform all reactants into products, equilibrium occurs. Many chemical processes eventually reach a state of balance or dynamic equilibrium where both reactants and products are present.

Learn more about equilibrium

brainly.com/question/11336012

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6 0
2 years ago
Which of the following solutions contains the greatest number of ions?
Elden [556K]

Answer : The correct option is, (A) 300.0 mL of 0.10 M CaCl₂

Explanation :

<u>(a) 300.0 mL of 0.10 M CaCl₂</u>

The dissociation reaction will be:

CaCl_2(aq)\rightarrow Ca^{2+}(aq)+2Cl^-(aq)

To calculate the number of moles of CaCl₂ as :

\text{Moles of }CaCl_2=\text{Concentration of }CaCl_2\times \text{Volume of solution in L}

\text{Moles of }CaCl_2=0.10M\times 0.3L=0.03mol

As, 1 mole of CaCl₂ contains ions = 3

So, 0.03 mole of CaCl₂ contains ions = 0.03 × 3 = 0.09 ions.

<u>(b) 400.0 mL of 0.10 M NaCl</u>

The dissociation reaction will be:

NaCl(aq)\rightarrow Na^{+}(aq)+Cl^-(aq)

To calculate the number of moles of NaCl as :

\text{Moles of }NaCl=\text{Concentration of }NaCl\times \text{Volume of solution in L}

\text{Moles of }NaCl=0.10M\times 0.4L=0.04mol

As, 1 mole of NaCl contains ions = 2

So, 0.04 mole of NaCl contains ions = 0.04 × 2 = 0.08 ions.

<u>(c) 200.0 mL of 0.10 M FeCl₃</u>

The dissociation reaction will be:

FeCl_3(aq)\rightarrow Fe^{3+}(aq)+3Cl^-(aq)

To calculate the number of moles of FeCl₃ as :

\text{Moles of }FeCl_3=\text{Concentration of }FeCl_3\times \text{Volume of solution in L}

\text{Moles of }FeCl_3=0.10M\times 0.2L=0.02mol

As, 1 mole of FeCl₃ contains ions = 4

So, 0.02 mole of FeCl₃ contains ions = 0.02 × 4 = 0.08 ions.

<u>(d) 800.0 mL of 0.10 M sucrose</u>

The dissociation of sucrose is not possible because it is a non-electrolyte.

To calculate the number of moles of sucrose as :

\text{Moles of }sucrose=\text{Concentration of }sucrose\times \text{Volume of solution in L}

\text{Moles of }sucrose=0.10M\times 0.8L=0.08mol

As, 1 mole of sucrose contains ions = 1

So, 0.08 mole of sucrose contains ions = 0.08 × 1 = 0.08 ions.

Hence, the solutions contains the greatest number of ions is, 300.0 mL of 0.10 M CaCl₂

3 0
3 years ago
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