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2 years ago

1 ll cm 5 cm 5 cm Surface area

Mathematics

1 answer:

djyliett [7]2 years ago

8 0

Answer:

pls send the image along with it. So it can be solved

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What is the value of the expression below?<br><br> 0.72/0.36*2

Tanya [424]

Answer:

Step-by-step explanation:

0.72/0.36 x 2

0.72/0.72

I'm always happy to help :)

8 0

3 years ago

Karen has 6 more than twice as many newspaper customers as when she started selling newspapers. She now has 98 customers. How ma

Black_prince [1.1K]

Answer:

46 customers

Step-by-step explanation:

If the number of original customers is n, we can write the following equation:

98 = 2n + 6

92 = 2n

46 = n

5 0

3 years ago

What is the mean of 90, 55, 75, 60, 80, and 90?

ElenaW [278]

90+55+75+60+80+90=450
450/6=75

8 0

3 years ago

Read 2 more answers

Which equation shows the quadratic formula used correctly to solve 5x2 + 3x – 4 = 0 for x? x = StartFraction negative 3 plus-or-

Brrunno [24]

Answer: FIRST OPTION

Step-by-step explanation:

<h3> The missing picture is attached.</h3>

By definition, given a Quadratic equation in the form:

$ax^2+bx+c=0$

Where "a", "b" and "c" are numerical coefficients and "x" is the unknown variable, you caN use the Quadratic Formula to solve it.

The Quadratic Formula is the following:

$x=\frac{-b \±\sqrt{b^2-4ac} }{2a}$

In this case, the exercise gives you this Quadratic equation:

$5x^2 + 3x - 4 = 0$

You can identify that the numerical coefficients are:

$a=5\\\\b=3\\\\c= - 4$

Therefore, you can substitute values into the Quadratic formula shown above:

$x=\frac{-b \±\sqrt{b^2-4ac} }{2a}\\\\x=\frac{-3 \±\sqrt{(3)^2-4(5)(-4)} }{2(5)}$

You can identify that the equation that shows the Quadratic formula used correctly to solve the Quadratic equation given in the exercise for "x", is the one shown in the First option.

6 0

3 years ago

Read 2 more answers

In circle P with mNRQ = 60°, find the angle measure of minor arc NQ

Galina-37 [17]

Given:

m∠NRQ = 60°

To find:

The angle measure of minor arc NQ

Solution:

The inscribed angle is half of the intercepted arc.

$$\Rightarrow m\angle NRQ =\frac{1}{2} m(ar NQ)$

Multiply by 2 on both sides.

$$\Rightarrow 2 \times m\angle NRQ =2 \times \frac{1}{2} m(ar NQ)$

$$\Rightarrow 2 \ m\angle NRQ =m(ar NQ)$

Substitute m∠NRQ = 60°.

$$\Rightarrow 2\times 60^\circ=m(ar NQ)$

$$\Rightarrow 120^\circ=m(ar NQ)$

The measure of minor arc NQ is 120°.

8 0

3 years ago

1 ll cm 5 cm 5 cm Surface area​

1 ll cm 5 cm 5 cm Surface area