Answer:
y = -31/5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = 2x - 7
5x + 2 = 4
<u>Step 2: Solve for </u><em><u>x</u></em>
- Define equation: 5x + 2 = 4
- Subtract 2 on both sides; 5x = 2
- Divide 5 on both sides: x = 2/5
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define equation: y = 2x - 7
- Substitute in <em>x</em>: y = 2(2/5) - 7
- Multiply: y = 4/5 - 7
- Subtract: y = -31/5
The correct option is C
Containing both apples and oranges.
<h3>What is
permutation and combination?</h3>
Combination and permutation are two methods for breaking down a set of objects into smaller groups. Any arrangement is possible when combining the parts of the subset. The parts of the subset are listed in a permutation in some certain order.
<h3>Briefing of the given statement:</h3>
The "apples and oranges" box needs to be opened, according to the briefing. By definition, the only type of fruit in the box is the one that is inside. Let's imagine you found one apple in the box that was marked with both the words "apples" and "oranges" on the label. You deduce that the box marked "apples" must subsequently only contain apples and that the box marked "oranges" cannot contain only oranges because all of the boxes have supposedly been labeled incorrectly. The box labeled "oranges" must therefore contain both apples and oranges, whereas the box labeled "apples" may only contain oranges.
To know more about permutation and combination visit:
brainly.com/question/13720848
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I understand that the question you are looking for is:
There are three boxes, one contains only apples, one contains only oranges, and one contains both apples and oranges. The boxes have been incorrectly labeled such that no label identifies the actual contents of the box it labels. Opening just one box, and without looking in the box, you take out one piece of fruit. By looking at the fruit, you can immediately label all of the boxes correctly. Which box did you open?
A. Containing apple
B. Containing oranges
C. Containing both apples and oranges
D. Cannot be determined
Answer:
GCD(343,550) = 1
LCM(343,550) = 188650
GCD(89,110) = 1
LCM(89,110) = 9790
GCD(870,222) = 6
LCM(870,222) = 32190
Step-by-step explanation:
a) GCD(343,550)
343 - 550 | 1
...
There are no values for which both 343 and 550 are divisible by, so GCD(343,550)=1.
LCM(343,550)
343 - 550 | 2
343 - 275 | 5
343 - 55 | 5
343 - 11 | 7
49- 11 | 7
7 - 11 | 7
1 - 11 | 11
1 - 1
So LCM(343,550) = 2*5*5*7*7*7*11 = 188650
b) GCD(89,110)
Again, as in a), there are no values for which 89 and 110 are divisible by. So GCD(89,110) = 1.
LCM(89,110)
89 - 110 | 2
89 - 55 | 5
89 - 11 | 11
89 - 1 | 89
1 - 1
So LCM(89,110) = 2*5*11*89 = 9790
c) GCD(870,222)
870 - 222 | 2
435 - 111 | 3
145 - 37
There are no numbers for which 145 and 37 are both divisible by, so the algorithm ends there, and GCD(870,222) = 2*3 = 6
LCM(870,222)
870 - 222 | 2
435 - 111 | 3
145 - 37 | 5
29 - 37 | 29
1 - 37 | 37
1 - 1
So LCM(870,222) = 2*3*5*29*37 = 32190
Answer:
0.216 seconds
Step-by-step explanation: 3 minutes and 51 seconds in seconds is 231 seconds so you just do 50 divided by 231