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Katen [24]
2 years ago
6

Please answer this with explanation. Please I really am struggling. I will mark you brainalist. Please solve it Please

Mathematics
1 answer:
Hatshy [7]2 years ago
8 0

Answer:

13, 11, 4, 16, 6, 22

Step-by-step explanation:

<em>Let the second digit be x and the last digit be y</em>

Given:

  • Data set: 13, x, 4, 16, 6, y
  • Mean = 12
  • y = 2x or x = 2y

The mean of the data is the average. The average can be calculated by determining the sum of the terms and dividing it by the total digits.

\implies \text{Mean of data:} \ \dfrac{13 + x + 4 + 16 + 6 + y}{6} = 12

Let us substitute the value of y (2x) in the data.

\implies \dfrac{13 + x + 4 + 16 + 6 + 2x}{6} = 12

Now, add all the terms in the data and simplify.

\implies \dfrac{39 + x +2x}{6} = 12

\implies \dfrac{39 + 3x}{6} = 12

Distribute the denominators and simplify.

\implies \dfrac{39}{6} + \dfrac{3x}{6}  = 12

\implies  \dfrac{13}{2} + \dfrac{x}{2}  = 12

\implies  6.5 + \dfrac{x}{2}  = 12

Subtract 6.5 both sides and simplify.

\implies  6.5 + \dfrac{x}{2}  - 6.5 = 12 - 6.5

\implies \dfrac{x}{2} = 5.5

Use cross multiplication and simplify.

\implies x= 5.5 \times 2

\implies  x= 11

To determine the value of "y", simply substitute the value of "x" into the expression that represents the value of "y".

\implies y = 2x

\implies y = 2(11)

\implies y = 22

When the x and y values are substituted in the data, we get;

  • ⇒ 13, 11, 4, 16, 6, 22

Therefore, the data is 13, 11, 4, 16, 6, 22.

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= 2(11) + 5
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= 27</span>
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An object at the top of a building with height 110 feet is thrown upward with an initial speed of 23 ft/s. Find its position z(t
alina1380 [7]

Answer:

Step-by-step explanation:

Given

Height of building is h=110\ ft

Initial upward velocity u=23\ ft/s

height of object is given by

z(t)=ut+\frac{1}{2}gt^2

but building is already at a height of 110 ft so z(t) must be given by

Z(t)=ut+\frac{1}{2}(-g)t^2+110

Z(t)=23\times t-\frac{1}{2}\times 9.8\times t^2

Z(t)=-16t^2+23t+110

Time when it hits is given by when Z(t)=0[/tex]

-16t^2+23t+110=0

t=\frac{-23\pm \sqrt{(23)^2-4\times (-16)\times 110}}{2\times (-16)}

t=\frac{-23\pm 87}{-32}

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6 0
4 years ago
Describe a triangle for which the centroid, circumcenter, incenter, and orthocenter are the same point. What features of this tr
hjlf

Answer:

An equilateral triangle

Step-by-step explanation:

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3 years ago
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I need help please.....
maria [59]
Here, Function: h(t)= -16t² + 70t + 40

So, put the value of t, (time at which you want to calculate the height)

h(1) = -16(1)² + 70(1) + 40
h(1) = -16 + 110
h(1) = 94

Now, h(2) = -16(2)² + 70(2) + 40
h(2) = -64 + 180
h(2) = 116

h(3) = -16(3)² + 70(3) + 40
h(3) = -144 + 250
h(3) = 106

In short, Your height depends on time, and at each time it would be different, can be expressed by the coordinates on a Graph: (1, 94) (2, 116) (3, 106)

Hope this helps!


8 0
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