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Anna71 [15]
4 years ago
12

Au(NO3)3 added with water? Aq or s?

Chemistry
1 answer:
Reptile [31]4 years ago
4 0
Gold (III) nitrate in an aqueous solution is hydrolyzed with formation of gold (III) metahydroxide.

Au(NO₃)₃ → Au³⁺(aq) + 3NO₃⁻(aq)

Au³⁺ + H₂O ⇄ AuOH²⁺ + H⁺
AuOH²⁺ + H₂O ⇄ Au(OH)₂⁺ + H⁺
Au(OH)₂⁺  + H₂O → AuOOH·H₂O(s) + H⁺

Au(NO₃)₃(aq) + 2H₂O(l) = AuOOH(s) + 3HNO₃(aq)
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Which of the following distinguishes a nuclear reaction from a chemical reaction? a.It involves atoms.
Leokris [45]
The answer is:
A. <span>It involves atoms. </span>
8 0
4 years ago
What are the elements in group two called
mina [271]

Answer: Alkaline-earth metal, any of the six chemical elements that comprise Group 2 (IIa) of the periodic table. The elements are beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra). Hopefully i helped

Explanation:

7 0
3 years ago
Read 2 more answers
What is the pH of a 3.5 x 10-5 M solution of HCl?
kolezko [41]

Answer:

4.46

Explanation:

Applying,

pH = -log(H⁺)....................... Equation 1

Where H⁺ = Hydrogen ion concentration of HCl solution

From the question,

Given: H⁺ =  3.5×10⁻⁵ M

Substitute these values into equation 1

pH = -log(3.5×10⁻⁵)

pH = 4.46

Hence the pH of HCl solution is 4.46

4 0
3 years ago
What volume (in liters, at 703 k and 2.04 atm) of chlorine gas is required to react with 3.39 g of p?
Natali5045456 [20]

The volume of chlorine required is 7.71 L.

The reaction between phosphorus and chlorine is:

2P + 5Cl₂→ 5PCl₅

Therefore, 2  moles of P requires 5 moles of chlorine to react with it.

Given mass of P =3.39 g

Molar mass of P=30.97 g/mol

No. of moles of P = given mass/ molar mass = 3.39 / 30.97 = 0.109 moles

2  moles of P requires 5 moles of chlorine

0.109  moles of P will require 0.109 x 5/2 = 0.2725 moles of chlorine

According to ideal gas equation

PV=nRT

2.04 x V = 0.2725 x 0.0821 x 703

V = 0.2725 x 0.0821 x 703 / 2.04

V = 7.71L

Learn more about ideal gas equation here:

brainly.com/question/3637553

#SPJ4                      

5 0
2 years ago
What is the total number of moles of O2(g) that must react completely with 5.00 moles of C4H10(g)?
Naddika [18.5K]

Answer:

32.5 moles of O2(g) are necessaries for a complete reaction

Explanation:

Based on the reaction of combustion of C4H10(g):

C4H10(g) + 13/2 O2(g) → 4CO2(g) + 5H2O(g)

<em>1 mole of C4H10 needs 13/2 moles O2 for a complete reaction.</em>

<em />

That means, the moles of O2 required for a reaction of 5.00 moles of C4H10 are:

5.00 moles C4H10 * (13/2mol O2 / 1mol C4H10) =

32.5 moles of O2(g) are necessaries for a complete reaction

4 0
3 years ago
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