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WARRIOR [948]
3 years ago
14

I need help with my chemistry homework please & thank u

Chemistry
1 answer:
lisov135 [29]3 years ago
5 0

Answer:

6) solid- dots close together

liquid- a little bit farther apart than solid

gas- far apart

7) the movement of anything from a higher area of concentration to an area of lower concentration.

8) B. evaporation

9) The solute is the thing being dissolved, the solvent is the thing dissolving it, and the solution is the product of the solute and solvent.

10) D. regular brewed coffee

*I'm not exactly sure on #10 but I hope I could've helped a little at least

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Calculate the pH of a 0.02 M solution of ascorbic acid ( K a1 = 7.9 × 10 –5; K a2 is 1.6 × 10 –12).
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C

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The student plans to conduct a spectrophotometric analysis to determine the concentration of Cu2+(aq) in a solution. The solutio
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The wavelength the student should use is 700 nm.

Explanation:

Attached below you can find the diagram I found for this question elsewhere.

Because the idea is to minimize the interference of the Co⁺²(aq) species, we should <u>choose a wavelength in which its absorbance is minimum</u>.

At 400 nm Co⁺²(aq) shows no absorbance, however neither does Cu⁺²(aq). While at 700 nm Co⁺²(aq) shows no absorbance and Cu⁺²(aq) does.

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Write the symbol for every chemical element that has atomic number greater than 3 and atomic mass less than 15.4 u.
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2 years ago
Nitrogen and oxygen do not react appreciably at room temperature, as illustrated by our atmosphere. But at high temperatures, th
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Answer : The equilibrium concentration of NO is, 0.0092 M.

Solution :

First we have to calculate the concentration of NO.

\text{Concentration of NO}=\frac{\text{Moles of }NO}{\text{Volume of solution}}=\frac{0.3152mol}{2.0L}=0.1576M

The given equilibrium reaction is,

                           N_2(g)+O_2(g)\rightleftharpoons 2NO(g)

Initially conc.      0        0           0.1576

At eqm.               (x)       (x)        (0.1576-2x)

The expression of K_c will be,

K_c=\frac{[NO]^2}{[N_2][O_2]}

0.0153=\frac{(0.1576-2x)^2}{(x)\times (x)}

By solving the term, we get:

x=0.0742,0.0839

Neglecting the 0.0839 value of x because it can not be more than initial value.

Thus, the value of 'x' will be, 0.0742 M

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Therefore, the equilibrium concentration of NO is, 0.0092 M.

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