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Bumek [7]
4 years ago
7

Which of the following reactions are redox reactions? Which of the following reactions are redox reactions? Ca(s)+Cl2(g)→CaCl2(s

) HCl(aq)+NaOH(aq)→H2O(l)+NaCl(aq) Zn(s)+Fe2+(aq)→Zn2+(aq)+Fe(s) Ba(NO3)2(aq)+K2SO4(aq)→BaSO4(s)+2KNO3(aq)
Chemistry
1 answer:
anastassius [24]4 years ago
7 0

Answer :  The redox reactions are:

Ca(s)+Cl_2(g)\rightarrow CaCl_2(s)

Zn(s)+Fe^{2+}(aq)\rightarrow Zn^{2+}(aq)+Fe(s)

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

(1) Ca(s)+Cl_2(g)\rightarrow CaCl_2(s)

This reaction is a redox reaction.

In this reaction, the oxidation state of 'Ca' changes from (0) to (+2) that means 'Ca' lost 2 electrons and it shows oxidation reaction and the oxidation state of 'Cl' changes from (0) to (-1) that means 'Cl' gain 1 electron and it shows reduction reaction.

(2) HCl(aq)+NaOH(aq)\rightarrow H_2O(l)+NaCl(aq)

This reaction is a double-displacement reaction in which the cation of two reactants molecule exchange their places to give two different products.

In double-displacement reaction, the oxidation state of cation and anion remains same on both side of the reaction. So, it is not a redox reaction.

(3) Zn(s)+Fe^{2+}(aq)\rightarrow Zn^{2+}(aq)+Fe(s)

This reaction is a redox reaction.

In this reaction, the oxidation state of 'Zn' changes from (0) to (+2) that means 'Zn' lost 2 electrons and it shows oxidation reaction and the oxidation state of 'Fe' changes from (+2) to (0) that means 'Fe' gain 2 electron and it shows reduction reaction.

(4) Ba(NO_3)_2(aq)+K_2SO_4(aq)\rightarrow BaSO_4(s)+2KNO_3(aq)

This reaction is a double-displacement reaction in which the cation of two reactants molecule exchange their places to give two different products.

In double-displacement reaction, the oxidation state of cation and anion remains same on both side of the reaction. So, it is not a redox reaction.

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The complete question is shown on the first uploaded image

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The value is  K_c  =  2.69 *10^{-5}  

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From the question we are told that

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Here [H_2O] is the concentration of water vapor which is mathematically represented as

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Here V_s is the volume of the solution given as 8.9 L

n_w is the number of moles of water vapor which is mathematically represented as

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and   Z_w  is the molar mass of water with value  18 g/mol

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[H] is the concentration of hydrogen gas which is mathematically represented as

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Here V_s is the volume of the solution given as 8.9 L

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So

     K_c  =  \frac{( 0.01236 )^3}{ (0.265 )^2}

=>   K_c  =  2.69 *10^{-5}  

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