After the water is boiled off, the mass is 9.7 grams, so find the weight of the water.
12.98 - 9.7 = 3.28g H2O
Find how many moles of CuSO4 and H2O you have.
If there are about 18g per mole of H2O
3.28/18 = .1822 moles of H2O
If there are about 160g per mole of CuSO4
9.7/160 = .0606 moles of CuSO4
.1822/.0606 = 3
Ratio of H2O to CuSO4 = 1:3
Formula
<span>CuSO4.3H2O
</span>
Full Name
<span>Copper (II) Sulphate Trihydrate</span>
Answer:
D)
Explanation:
I just answered the question and got it right.
To find moles : moles= Mass (C₄H₂O₄) / RFM (C₄H₂O₄)
so moles = 147.7 / 114 = <span>1.2956mol
hope that helps </span>
Answer:
CH3 – CH – CH – CH2 – CH – CH3
| | |
CH3 CH2 CH3
|
CH3
Explanation:
3 - etil - 2, 5 - dimetilhexano
