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3 years ago

IDENTIFY WHICH PROPERTIES COULD CORRESPOND TO SOLIDS PLASMAS OR BOTH

2 answers:

8 0

Answer is: solid is the state in which matter has a definite shape and volume.There are two types of solids:crystalline (solids that have a very orderly, 3-dimentional arrangement of atoms or molecules) and amaorphous (composed of atoms or molecules that are in no particular order).
Plasma is is the state of matter that does not have a definite shape or volume. <span>Plasmas and some solids (metals) conduct electric current.</span>

MrMuchimi3 years ago

3 0

Identify which properties could correspond to solids, plasmas, or both.

solids maintain a unique shape.

plasma particles collide infrequently with other particles.

plasma particles have very high velocities.

both solids and plasmas can conduct electricity.

both solids and plasmas contain protons.

solids typically have a low temperature.

solid structure has long-range order.

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How many moles are in 7.2x10^15 atoms of Pb?

fiasKO [112]

<h3>Answer:</h3>

1.2 × 10⁻⁸ mol Pb

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 7.2 × 10¹⁵ atoms Pb

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 7.2 \cdot 10^{15} \ atoms \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ atoms \ Pb})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 1.19562 \cdot 10^{-8} \ mol \ Pb$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.19562 × 10⁻⁸ mol Pb ≈ 1.2 × 10⁻⁸ mol Pb

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What's the answer to number 5? I need the answer quickly please

Anton [14]

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ololo11 [35]

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bezimeni [28]

The awnser would be c i got you fam

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