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Mandarinka [93]
3 years ago
11

I need help on a homework question.

Physics
2 answers:
Mama L [17]3 years ago
7 0

Answer:

green

Explanation:

the the board is going to be green

Marta_Voda [28]3 years ago
6 0
C. Green I think sorry if I’m wrong
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A 2 kg block moves along x axis . if acceleration as function of its ​
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A 2-kg object is moving 6 m/s in a horizontal direction.
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Answer: A) O N

Explanation:

An object in motion will maintain its state of motion. The presence of an unbalanced force changes the velocity of the object.

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Which statement best compares momentum and kinetic energy? If you double the velocity of an object, its kinetic energy doubles.
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Matt is driving down 7th street. He drives 150 meters in 18 seconds. Assuming he does not speed up or slow down, what is his spe
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3 years ago
Even when the head is held erect, as in the figure below, its center of mass is not directly over the principal point of support
alexandr1967 [171]

We are asked to determine the force required by the neck muscle in order to keep the head in equilibrium. To do that we will add the torques produced by the muscle force and the weight of the head. We will use torque in the clockwise direction to be negative, therefore, we have:

\Sigma T=r_{M\perp}(F_M)-r_{W\perp}(W)

Since we want to determine the forces when the system is at equilibrium this means that the total sum of torque is zero:

r_{M\perp}(F_M)-r_{W\perp}(W)=0

Now, we solve for the force of the muscle. First, we add the torque of the weight to both sides:

r_{M\perp}(F_M)=r_{W\perp}(W)

Now, we divide by the distance of the muscle:

(F_M)=\frac{r_{W\perp}(W)}{r_{M\perp}}

Now, we substitute the values:

F_M=\frac{(2.4cm)(50N)}{5.1cm}

Now, we solve the operations:

F_M=23.53N

Therefore, the force exerted by the muscles is 23.53 Newtons.

Part B. To determine the force on the pivot we will add the forces we add the vertical forces:

\Sigma F_v=F_j-F_M-W

Since there is no vertical movement the sum of vertical forces is zero:

F_j-F_M-W=0

Now, we add the force of the muscle and the weight to both sides to solve for the force on the pivot:

F_j=F_M+W

Now, we plug in the values:

F_j=23.53N+50N

Solving the operations:

F_j=73.53N

Therefore, the force is 73.53 Newtons.

8 0
1 year ago
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