<span>The volume of a cube is given by s^3. So the volume of this block is 3cm x 3cm x3 cm = 27 cm^3. density = mass/volume =27 g / 27 cm^3 = 1 g/cm^3.</span>
Answer:
The original volume of the first bar is half of the original volume of the second bar.
Explanation:
The coefficient of cubic expansivity of substances is given by;
γ = ΔV ÷ (Δθ)
Given: two metal bars with equal change in volume, equal change in temperature.
Let the volume of the first metal bar be represented by , and that of the second by .
Since they have equal change in volume,
Δ = Δ = ΔV
For the first metal bar,
2γ = ΔV ÷ (Δθ)
⇒ Δθ = ΔV ÷ (2γ)
For the second metal bar,
γ = ΔV ÷ (Δθ)
⇒ Δθ = ΔV ÷ (γ)
Since they have equal change in temperature,
Δθ of first bar = Δθ of the second bar
ΔV ÷ (2γ) = ΔV ÷ (γ)
So that;
(1 ÷ 2) = (1 ÷ )
2 =
=
Thus, original volume of the first bar is half of the original volume of the second bar.
Answer:
It spreads out into multiple shadow regions
Explanation:
- when the waves meet the barrier than light is diffracted as When this occurs, the wave bends around the corners of the barrier or passes through the opening of the wedge, which acts as a barrier, forming several patterns with the hole shape of the wedge.
- and The main condition for this phenomenon to occur is that the magnitude of the barrier must be equal to the magnitude of the wavelength.
- when sunlight as an electromagnetic waves is passes by key hole of gate, then this light will break and form many keyhole-shaped shadow fields.
Answer:
11.3 g
Explanation:
given,
density of the lead = 11.3 g/cm³
volume = 1 cm³
mass of the lead = ?
we know,
mass = volume x density
mass = 1 x 11.3
mass = 11.3 g
hence, the mass of the lead is equal to 11.3 g
Answer:
Momentum is always conserved, and kinetic energy may be conserved.
Explanation:
For an object moving on a horizontal, frictionless surface which makes a glancing collision with another object initially at rest on the surface, the type of collision experienced by this objects can either be elastic or an inelastic collision depending on whether the object sticks together after collision or separates and move with a common velocity after collision.
If the body separates and move with a common velocity after collision, the collision is elastic but if they sticks together after collision, the collision is inelastic.
Either ways the momentum of the bodies are always conserved since they will always move with a common velocity after collision but their kinetic energy may or may not be conserved after collision, it all depends whether they separates or stick together after collision and since we are not told in question whether or not they separate, we can conclude that their kinetic energy "may" be conserved.