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4 years ago

Which one of the following accurately pairs the device with its function?

Physics

2 answers:

iren [92.7K]4 years ago

3 0

Its A. Bourdon gage - indicate steam pressure in a furnace.

Ne4ueva [31]4 years ago

3 0

your answer is A: Bourdon gage-indicate steam pressure in a furnace.

i just took the test

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What are 5 different ways to use a fidget spinner?

butalik [34]

Answer:

Balancing on one finger.

Tossing between hands.

Using a different body part.

Building a tower.

Throwing it high in the air.

Flipping it over.

Switching between fingers.

Going behind the back.

Explanation:

Just stuff I used to do ^^

5 0

3 years ago

A mixing blade on a food processor extends out 3 inches from its center. if the blade is turning at 600 revolutions per minute,

7nadin3 [17]

First let's convert everything into SI units.
The length of the blade is 3 inches. Keeping in mind that 1 inc=0.025 m, we have
$L=3 in \cdot 0.025 \frac{m}{inc} =0.075 m$
The angular speed is 600 revolutions per minute. Keeping in mind that $1 rev=2 \pi rad$ and $1 min=60 s$ , the angular speed becomes
$\omega = 600 \frac{rev}{min} \frac{2 \pi rad/rev}{60 s/min}=62.8 rad/s$

And so, the linear velocity of the edge of the blade is equal to
$v=\omega L=(62.8rad/s)(0.075 m)=47 m/s$

8 0

3 years ago

Read 2 more answers

A projectile of mass 9.6 kg is launched from the ground with an initial velocity of 12.4 m/s at angle of 54° above the horizonta

Temka [501]

Answer:

The location is at (3.535, 1.162) m

Solution:

As per the question:

Mass of the projectile, m = 9.6 kg

Initial velocity, v = 12.4 m/s

Angle, $\theta = 54^{\circ}$

Mass of one fragment, m = 6.5 kg

Time taken by the fragment, t = 1.42 s

Height of the fragment, y = 5.9 m

Horizontal distance, x = 13.6 m

Now,

To determine the location of the second fragment:

Horizontal Range, $R = \frac{v^{2}sin2\theta}{g}$

$R = \frac{12.4^{2}sin2(54)}{9.8} = 14.92\ m$

Time of flight, t' = $\frac{2vsin\theta}{g} = \frac{2\times 12.4sin108}{9.8}= 2.406\ s$

Now, for the fragments:

Mass of the other fragment, m' = M - m = 9.6 - 6.5 = 3.1 kg

Distance traveled horizontally:

$s_{x} = vcos\theta = 12.4cos54^{\circ}\times 1.42 = 10.35\ m$

Distance traveled vertically:

$s_{y} = vcos\theta - \frac{1}{2}gt^{2}$

$s_{y} = 12.4sin54^{\circ}\times 1.42 - \frac{1}{2}\times 9.8\times 1.42^{2} = 14.25 - 9.88 = 4.37\ m$

Now,

$s_{x} = \frac{mx + m'x'}{M}$

$10.35= \frac{6.5\times 13.6 + 3.1x'}{9.6}$

x' = 3.535 m

Similarly,

$s_{y} = \frac{my + m'y'}{M}$

$4.37= \frac{6.5\times 5.9 + 3.1y'}{9.6} = 1.162\ m$

The location of the other fragment is at (3.535, 1.162)

5 0

4 years ago

A 14.0 g wad of sticky clay is hurled horizontally at a 110 g wooden block initially at rest on a horizontal surface. The clay s

ahrayia [7]

Answer:

86.53 m/s

Explanation:

Given:

Mass of clay (m) = 14.0 g = 0.014 kg

Mass of block (M) = 110 g = 0.110 kg

Initial speed of block (U) = 0 m/s

Sliding distance (d) = 7.50 m

Coefficient of friction between block and surface (μ) = 0.650

Let the initial speed of clay be 'u' and speed of clay and block just after collision be 'v'.

Now, momentum is conserved just before and just after collision.

Momentum just before collision = $mu + 0 = mu$

Momentum just after collision = $(m + M)v$

Therefore, $mu=(M+m)v$ --------- (1)

Now, using newton's second law and we find the acceleration of the system.

The frictional force is given as:

$f=\mu mg=-ma\\\\a=-\mu g$

Now, using equation of motion, we can find the velocity just after collision.

$0^2=v^2+2ad\\\\v=\sqrt{-2ad}\\\\v=\sqrt{-2\times (-\mu g)\times d}\\\\v=\sqrt{2\mu gd}$

Plug in the given values and find 'v'. This gives,

$v=\sqrt{2\times 0.650\times 9.8\times 7.50}\\\\v=\sqrt{95.55}=9.77\ m/s$

Now, using equation (1) and substituting the given values, we get:

$0.014u=(0.014+0.110)\times 9.77\\\\u=\frac{0.124\times 9.77}{0.014}\\\\u=86.53\ m/s$

Therefore, the speed of the clay immediately before impact is 86.53 m/s.

7 0

3 years ago

This equation shows the reaction that occurs when charcoal burns. What type<br> of reaction is it?

TiliK225 [7]

Explanation:

Exothermic

Because here Energy is released.

3 0

3 years ago

Read 2 more answers