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exis [7]
2 years ago
11

What foods of the aztec found their way into mayan cooking?.

Chemistry
1 answer:
Lera25 [3.4K]2 years ago
7 0

Avocados and tomatoes were mainly eaten by the Aztecs and Maya.

<h3>How did Mayans cook their food?</h3>

"Mayans cooking method includes digging a shallow pit, lining it with stones or clay balls.

Avocados and tomatoes were mainly eaten by the Aztecs and Maya, with different types of fruit. Corn was made into a kind of porridge, called atole in Mesoamerica and capita in Inca territory.

Avocados and tomatoes were mainly eaten by the Aztecs and Maya.

Learn more about Mayan cooking here:

brainly.com/question/1979880

#SPJ1

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If it takes 22974 J to heat 96.5 g of a substance from 13.46°C to 73.86 °C, what is the specific heat of the substance?​
yulyashka [42]

The specific heat capacity, C, of the substance is 3.94 \frac{J}{g-^oC}. To raise one gram of a substance by one degree Celsius, a specific amount of heat must be absorbed. This is called the specific heat of the substance. The higher the specific heat of a substance, the more energy is needed to increase its temperature and vice versa.

<u>Further Explanation: </u>

The specific heat capacity, C, of a substance is related to the amount of substance and the temperature change using the following equation

q \ = \ mC(T_{f}-T_{i})

where

q = amount of heat absorbed (usually in J)

m = amount of substance (in g)

C = specific heat capacity (in \frac{J}{g-^oC})

T(f) = final temperature

T(i) = initial temperature.

To answer the problem, we sort the given information:

q = 22974 J (5 significan figures)

m = 96.5 g (3 significant figures)

C = ?

T(f) = 73.86 °C (4 significant figures)

T(i) = 13.46 °C (4 significant figures)

Then, to find C, rearrange the equation:

C \ = \frac{q}{m(T_{f} \ - \ T_{i})}

Plug in the values to the equation above to get the value of C.

C \ = \ \frac{22974 \ J}{96.5 \ g \ (73.86 \ \ -13.46 \°C)} \\C \ = \ \frac{22974 \ J}{96.5 \ g \ (60.4\°C)} \\C \ = \ \frac{22974 \ J}{5828.6 \ g -\°C} \\C \ = \ 3.941598 \ \frac{J}{g -\°C} \\

Since the least number of significant figures in the given is 3, then the final answer must have 3 significant figures, too. Therefore,

\boxed {C = 3.94 \ \frac{J}{ g -\°C}}

<u></u>

<u>Learn More: </u>

1. Learn more about heat capacity brainly.com/question/8828503

2. Learn more about calorimetry brainly.com/question/8168263

3. Learn more about heat of reaction brainly.com/question/10122365

<u>Keywords:</u> heat capacity, specific heat, calorimetry

4 0
3 years ago
If the Earth is round... why is the land flat?
stiv31 [10]

Answer:

See explanation

Explanation:

The land around us appears flat because the Earth is just so unimaginably large, and the curvature is extremely small from our point of view. In reality, the land is slightly bendy, which is why certain structures (like very long bridges) need to be constructed with the curvature in mind, with different ends at slightly different elevations. Hope this helps!

4 0
2 years ago
Read 2 more answers
A loss of electrons by an atom creates an anion? <br> true or false
Nostrana [21]
That is false.

An ion is "<span>an electrically charged atom or group of atoms formed by the loss or gain of one or more electrons."

But in detail anion means gaining of electrons.

So, a gain of electrons by an atom creates an anion.</span>
4 0
2 years ago
Read 2 more answers
How many grams of sodium metal must be introduced to water to produce 3.3 grams of hydrogen gas?
Cloud [144]

Answer:

The mass of sodium metal that must be introduced to water to produce 3.3 grams of hydrogen gas, H₂, is approximately 18.82 grams of sodium metal

Explanation:

The given mass of hydrogen gas produced = 3.3 grams

The molar mass of hydrogen gas, H₂ = 2.016 g/mol

The number of moles of hydrogen gas in 3.3 grams of H₂, 'n', is given as follows;

n = Mass/(Molar mass)

n = 3.3 g/(2.016 g/mol) = 1.63690476 moles of H₂

The reaction of sodium and water can be written as follows;

2Na + 2H₂O → 2NaOH + H₂ (g)

2 moles of sodium produces 1 mole of hydrogen gas, H₂

Therefore;

1.63690476/2 moles of sodium will produce 1.63690476 moles of hydrogen gas, H₂

The molar mass of sodium, Na ≈ 22.989 g/mol

The mass of 1.63690476/2 moles of sodium, 'm', is given as follows;

m = 1.63690476/2 moles × 22.989 g/mol ≈ 18.8154018 grams ≈ 18.82 grams

The mass of sodium that will produce 3.3 grams of hydrogen, m ≈ 18.82 grams of sodium metal.

8 0
3 years ago
0.50 g of hydrogen chloride (HCl) is dissolved in water to make 4.0 L of solution. What is the pH of the resulting hydrochloric
svlad2 [7]

Explanation:

Given the mass of HCl is ---- 0.50 g

The volume of solution is --- 4.0 L

To determine the pH of the resulting solution, follow the below-shown procedure:

1. Calculate the number of moles of HCl given by using the formula:

number of moles of a substance=\frac{given mass of the substance}{its molecular mass}

2. Calculate the molarity of HCl.

3. Calculate pH of the solution using the formula:

pH=-log[H^+]

Since HCl is a strong acid, it undergoes complete ionization when dissolved in water.

HCl(aq)->H^+(aq)+Cl^-(aq)

Thus, [HCl]=[H^+]

Calculation:

1. Number of moles of HCl given:

number of moles of a substance=\frac{given mass of the substance}{its molecular mass}\\=0.50g/36.5g/mol\\=0.0137mol

2. Concentration of HCl:

Molarity of HCl=\frac{number of moles of HCl}{its molar mass}\\=\frac{0.0137 mol}{4.0 L} \\= 0.003425 M

3. pH of the solution:

pH=-log[H^+]\\=-log(0.003425)\\=2.47

Hence, pH of the given solution is 2.47.

3 0
3 years ago
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