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sertanlavr [38]
3 years ago
6

When 0.25 moles of NH3 are produced according to the reaction below, how many moles of H2 must have reacted?

Chemistry
2 answers:
marissa [1.9K]3 years ago
6 0

Answer:

Explanation:

by stoichiometry

nNH3/2=nH2/3

0.25/2=nH2/3

nH2=0.25×3/2

nH2=0.375 mol

so its 0.38 mol

Rina8888 [55]3 years ago
5 0

Answer:

I have this quiz rn I will try 0.38 if it is right I’ll edit this and say that

Explanation:

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agasfer [191]

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Explanation:

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5 0
3 years ago
2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
Harrizon [31]

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<u>Explanation:</u>

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We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}

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Explanation:

6 0
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