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lyudmila [28]
3 years ago
7

The law of partial pressures was developed by ___________.

Chemistry
1 answer:
fomenos3 years ago
3 0

Answer:

John Dalton

Explanation:

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Standard reduction half-cell potentials at 25∘c half-reaction e∘ (v) half-reaction e∘ (v) au3 (aq) 3e−→au(s) 1.50 fe2 (aq) 2e−→f
Zanzabum

<em>K</em> = 5.0 × 10^25

<h2>Part (a). Calculate <em>E</em>° for the reaction </h2>

<em>Step 1.</em> Write the equations for the two half-reactions

2H^(+)(aq) + 2e^(-) → H2(g); _0.00 V

Zn^(2+)(aq) + 2e^(-) → Zn(s); -0.76 V

<em>Step 2.</em> Identify the cathode and the anode

The half-cell with the more negative <em>E</em>° (Zn) is the anode.

<em>Step 3.</em> Calculate <em>E</em>°

Zn(s) → Zn^(2+)(aq) + 2e^(-); _________+0.76 V

2H^(+)(aq) + 2e^(-) → H2(g); __________0.00 V

Zn(s) + 2H^(+)(aq) → Zn^(2+)(aq) + H2(g); +0.76 V

<em>E</em>° = +0.76 V

<h2>Part (b). Calculate <em>K</em> for the reaction </h2>

The relation between <em>E</em>° and <em>K</em> is

<em>E</em>° = (<em>RT</em>)/(<em>nF</em>)ln<em>K </em>

where

<em>R</em> = the universal gas constant: 8.314 J·K^(-1)mol^(-1)

<em>T</em> = the Kelvin temperature

<em>n</em> = the moles of electrons transferred

<em>F</em> = the Faraday constant: 96 485 J·V^(-1)mol^(-1)

Then

0.76 V = [8.314 J·K^(-1)mol^(-1) × 298.15 K]/[2 × 96 485 J·V^(-1)mol^(-1)]ln<em>K</em>

0.76 = 0.012 85 ln<em>K</em>

ln<em>K</em> = 0.76/0.012 85 = 59.16

<em>K</em> =e^59.16 = 5.0 × 10^25

4 0
3 years ago
Which describes an effect that ocean currents have on short-term climate change? Ocean currents increase the strength of prevail
Luba_88 [7]

Answer:

All the option are correct

Explanation:

The ocean currents have been associated with past climatic shifts during critical periods (for example, the ice ages), where modifications in water circulation might have caused important climatic changes.

From a biological point of view, the ocean currents may be associated not only with the climate but also biogeochemical cycles through modifications in the distribution of heat and freshwater. Thus, the changes in ocean circulation may produce biogeographical shifts by affecting the local climate. The importance of ocean currents in affecting biodiversity is also represented by the equilibrium of coral reef ecosystems, where this equilibrium is broken up by factors such as transport of pollutants, temperature conditions, etc., which are known to alter thermosensitive coral species.

3 0
3 years ago
Read 2 more answers
A chemist prepares a solution of sodium thiosulfate by measuring out of sodium thiosulfate into a volumetric flask and filling t
marshall27 [118]

Mass of sodium thiosulfate Na_{2}S_{2}O_{3} is 110. g

Volume of the solution is 350. mL

Calculating the moles of sodium thiosulfate:

110. g Na_{2}S_{2}O_{3} * \frac{1 mol Na_{2}S_{2}O_{3}}{158.1 g Na_{2}S_{2}O_{3}} = 0.696 molNa_{2}S_{2}O_{3}

Converting the volume of solution to L:

350. mL * \frac{1 L}{1000 mL} = 0.350 L

Finding out the concentration of solution in molarity:

\frac{0.696 mol}{0.350 L} =  1.99 mol/L

4 0
3 years ago
Why is it usually warmer at Earth’s equator than at its poles?
MissTica

Answer:

the equator is closer to the sun

8 0
3 years ago
Calculate the concentration of CO2 in water at 25 degrees Celsius when the pressure of CO2 over the solution is 4.5 atm. At 25 d
OLEGan [10]

Answer : The concentration of CO_2 is, 0.12 M

Explanation :

Using Henry's law :

C_{CO_2}=k_H\times p_{CO_2}

where,

C_{CO_2} = concentration of CO_2 = ?

p_{CO_2} = partial pressure of CO_2 = 4.5 atm

k_H = Henry's law constant  = 3.1\times 10^{-2}mol/L.atm

Now put all the given values in the above formula, we get:

C_{CO_2}=3.1\times 10^{-2}mol/L.atm\times (4.5atm)

C_{CO_2}=0.1395M\approx 0.12M

Thus, the concentration of CO_2 is, 0.12 M

5 0
3 years ago
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