54. fluorine
55. oxygen
56. they have the same number of protons
57. nucleus 3
Explanation:
54. The element represented by the nucleus 1 have 9 protons and 9 neutrons. The atomic number of the element is equal to the number of protons = 9, so the element is fluorine.
55. The element represented by the nucleus 2 have 8 protons and 10 neutrons. The atomic number of the element is equal to the number of protons = 8, so the element is oxygen.
56. nucleus 2 contains 8 protons and 10 neutrons
nucleus 4 contains 8 protons and 11 neutrons.
The atoms that have the same number of protons but different number of neutrons are called isotopes.
57. nucleus 3 have 10 protons and 10 neutrons and correspond to neon. Neon have 10 electrons (equal to the number of protons) and have the electronic configuration 1s² 2s² 2p⁸. Because all the electrons shells are filled with electrons, neon have a stable electron configuration.
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Answer: The answer is D :)
Explanation:
Answer:
![H^++NH_3\rightleftharpoons NH_4^+](https://tex.z-dn.net/?f=H%5E%2B%2BNH_3%5Crightleftharpoons%20NH_4%5E%2B)
Explanation:
Hello there!
In this case, since the buffer is not given, we assume it is based off ammonia, it means the ammonia-ammonium buffer, whereas the ammonia is the weak base and the ammonium ion stands for the conjugate acid. In such a way, when adding HI to the solution, the base of the buffer, NH3, reacts with the former to promote the following chemical reaction:
![H^++NH_3\rightleftharpoons NH_4^+](https://tex.z-dn.net/?f=H%5E%2B%2BNH_3%5Crightleftharpoons%20NH_4%5E%2B)
Because the HI is totally ionized in solution so the iodide ion becomes an spectator one.
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