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iVinArrow [24]
3 years ago
11

A single die is rolled twice find the probability of rolling an even number the first time and a number greater than 5 the secon

d time

Mathematics
1 answer:
Troyanec [42]3 years ago
5 0
The probability of rolling of rolling an even number would be 3/6 because there are three even numbers out of six. If this were rolled twice, it'd be double (it'd become 6/12) 
then the probability of rolling a number greater than five on the second turn would be 1/6 because only one number is greater than five on a die, which is six. Again, if it were rolled twice, it'd be double (and become 2/12)
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Which of the following does not dissolve in water​
xeze [42]

Answer:

mud

Step-by-step explanation:

4 0
3 years ago
Solve the linear system by using Substitution. Enter your answer as an ordered pair.
MAXImum [283]

Answer: {y,x} = {4,2} ) ) ) )4

Step-by-step explanation: y

[2] y = -2x + 8

// Plug this in for variable y in equation [1]

[1] (-2x+8) - x = 2

[1] - 3x = -6

// Solve equation [1] for the variable x

[1] 3x = 6

[1] x = 2

// By now we know this much :

y = -2x+8

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7 0
3 years ago
Read 2 more answers
the temperature in winter night was -23 degrees Fahrenheit the temperature Rose by 5° when the sun rose when the sunset again th
expeople1 [14]

So we have -23 degrees to start

Then add 5 to it

It becomes -23+5=-18

Now subtract 7 from that so -18-7=-25 degrees

Hope this helps

8 0
3 years ago
When the expression $-2x^2-20x-53$ is written in the form $a(x+d)^2+e$, where $a$, $d$, and $e$ are constants, then what is the
Sladkaya [172]
We start with 2 x^{2} -20x-53 and wish to write it as a(x+d) ^{2} +e

First, pull 2 out from the first two terms: 2( x^{2} -10x)-53

Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have x^{2} -10x and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square: x^{2} -10x+25=(x-5) ^{2}

The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have 2( x-5) ^{2}-53 and when we multiply that out it does not give us what we started with. It gives us 2 x^{2} -20x+50-53=2 x^{2} -20x-3

So you see our expression is not right. It should have a -53 but instead has a -3. So to correct it we need to subtract another 50.

We do this as follows: 2(x-5) ^{2}-53-50 which gives us the final expression we seek:

2(x-5) ^{2}-103

If you multiply this out you will get the exact expression we were given. This means that:
a = 2
d = -5
e =  -103

We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106


7 0
3 years ago
Can y’all plz help me ?
crimeas [40]

Answer:

x=-5

Step-by-step explanation

The first box has eight x's and six 1's which means that it would be written as 8x+6

The second box has four x's and fourteen -1's which means that it would be written as 4x-14

You set them equal to one another

8x+6=4x-14

You subtract 4x from both sides

4x+6=-14

Subtract 6 on both sides

4x=-20

Divide 4 on both sides

x=-5

Hope it helps :))

4 0
3 years ago
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