The correct answer is
Energy of electrons depends on light’s frequency, not intensity.
As per photoelectric effect, if we incident a light on metal surface it will results into emission of electron from it
if we increase the number of photons the number of electrons will increase however if we increase the frequency the number of photons will not increase
While if we increase frequency the energy of electrons will increase as
Energy of photon = Work function of metal + kinetic energy of electrons
Ranking of the ions in each set in order of decreasing size -
Cs+ > Ba²⁺ > Sr²⁺
Cs+ has the biggest size, because its more downward (compared to Sr2+) and more to the left (compared) ot Ba2+.
Sr2+ has the smallest size because it's more upwords (compared to Cs+ and Ba2+).
For isoelectronic ions, the greater the nuclear charge , the greater is the attraction for electrons and smaller is ionic radius. In other words, size of the isoelectronic ions decreases with increase in atomic number.
Cl3+ has the smallest ion among all.
To learn more about ions from given link
brainly.com/question/14658491
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Answer:
Ron Clements and John Musker
Explanation:
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