Answer:
1. Cu
2. Cu
3. 2 electrons.
Explanation:
Step 1:
The equation for the reaction is given below:
3Cu(s) + 8HNO3(aq) -> 2NO(g) 3Cu(NO3)2(aq) + 4H2O(l)
Step 2:
Determination of the change of oxidation number of each element present.
For Cu:
Cu = 0 (ground state)
Cu(NO3)2 = 0
Cu + 2( N + 3O) = 0
Cu + 2(5 + (3 x -2)) =0
Cu + 2 (5 - 6) = 0
Cu + 2(-1) = 0
Cu - 2 = 0
Cu = 2
The oxidation number of Cu changed from 0 to +2
For N:
HNO3 = 0
H + N + 3O = 0
1 + N + (3 x - 2) = 0
1 + N - 6 = 0
N = 6 - 1
N = 5
NO = 0
N - 2 = 0
N = 2
The oxidation number of N changed from +5 to +2
The oxidation number of oxygen and hydrogen remains the same.
Note:
1. The oxidation number of Hydrogen is always +1 except in hydride where it is - 1
2. The oxidation number of oxygen is always - 2 except in peroxide where it is - 1
Step 3:
Answers to the questions given above
From the above illustration,
1. Cu is oxidize because its oxidation number increased from 0 to +2 as it loses electron.
2. Cu is the reducing agent because it reduces the oxidation number of N from +5 to +2.
3. The reducing agent i.e Cu transferred 2 electrons to the oxidising agent HNO3 because its oxidation number increase from 0 to +2 as it loses its electrons. This means that Cu transfer 2 electrons.
The percentage yield obtained from the given reaction above is 74.8%
<h3>Balanced equation </h3>
P₄ + 6Cl₂ → 4PCl₃
Molar mass of P₄ = 31 × 4 = 124 g/mol
Mass of P₄ from the balanced equation = 1 × 124 = 124 g
Molar mass of PCl₃ = 31 + (35.5×3) = 137.5 g/mol
Mass of PCl₃ from the balanced equation = 4 × 137.5 = 550 g
<h3>SUMMARY</h3>
From the balanced equation above,
124 g of P₄ reacted to produce 550 g of PCl₃
<h3>How to determine the theoretical yield </h3>
From the balanced equation above,
124 g of P₄ reacted to produce 550 g of PCl₃
Therefore,
79.12 g of P₄ will react to produce = (79.12 × 550) / 124 = 350.9 g of PCl₃
<h3>How to determine the percentage yield </h3>
- Actual yield of PCl₃ = 262.6 g
- Theoretical yield of PCl₃ = 350.9 g
Percentage yield = (Actual /Theoretical) × 100
Percentage yield = (262.6 / 350.9) × 100
Percentage yield = 74.8%
Learn more about stoichiometry:
brainly.com/question/14735801
Answer:
temporary changes are the changes which are there only for a short period if time.
Explanation:
generally temporary changes are reversible. permanent changes are the changes which remain for a longer time and are not reversible
The symbol for xenon (xe) would be a part of the noble gas notation for the element cesium.
For writing the electronic configuration of any element by using the preceding noble gas configuration, we simply use the symbols of noble gas belongs to the previous period of that particular elements. We can't use the symbol of noble gas of same period from which the element belong.
A is the wrong option because the noble gas in the preceding period to the period from which antimony belongs is krypton.
The actual electronic configuration of antimony is as follow:
[Kr] 4d10 5s2 5p3
B is correct option because the noble gas in the preceding period to the period from which Cesium belongs is Xenon.
The actual electronic configuration of Cesium is as follow:
[Xe] 6s1
Thus, we concluded that the symbol for xenon (xe) would be a part of the noble gas notation for the element cesium.
learn more about Noble gas:
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Answer:
well for me it's
Explanation:
The reflection of the seas
