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3 years ago

I’ll mark brainliest please

Chemistry

1 answer:

DaniilM [7]3 years ago

5 0

I’m assuming your just writing the formula? If so
Potassium chloride: KCL
Potassium nitride: KNO2
Potassium sulfide: K2S
calcium chloride: CaCl2
Calcium nitride: Ca3N2
Calcium sulfide: CaS
Silver chloride: AgCl
Silver nitride: Ag3N
Silver sulfide: Ag2S
Manganese (||) chloride: MnCl2
Manganese (||) nitride: Mn3N2
Manganese (||) sulfide: MnS

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From smallest to largest put these in order of their atomic radius Mg, Ba,

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Explanation:

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3 years ago

What is the wavelength of light emitted between the 3 rd and 1 st energy levels? 121.5 nm 94.5 nm 102.5 nm 1875 nm

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3 years ago

Which of the following would be classified as an acid to the Arrhenius definition

mixer [17]

Any substance that increases the concentration of $H^+$ in aqueous solutions is Arrhenius's acid.

<h3>What are Arrhenius acids?</h3>

Arrhenius define acids as substances with the chemical capacities to increase the concentration of hydrogen ion in aqueous solutions.

Thus, substances like HCl, HNO3, HBr, etc. would be considered an acid. This is because they ionize in aqueous solutions as follows:

HCl ---> $H^+$ + $Cl^-$

$HNO_3 --- > H^+ + NO_3^-$

$HBr --- > H^+ + Br^-$

More on Arrhenius acids can be found here: brainly.com/question/9936252

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4 0

2 years ago

Read 2 more answers

Does water added to a flask containing chlorine gas and solid sodium react in the chemical reaction to make sodium chloride

Jet001 [13]

Answer:

Explanation:

Chemically, we can have a reaction between chlorine gas and solid sodium

This reaction is actually explosive and would produce fine powder of sodium chloride

We have the reaction as follows:

$2Na_{(s)}+Cl_{2(g)}\rightarrow2NaCl_{(s)}$

Essentally, what we can deduce from here is that we do not need to add water to the flask. Except for the reason that we would want the sodium chloride solid in the solution form, there is absolutely no reason to add water to the flask as the reaction would proceed normally

5 0

1 year ago

For the reaction Na2CO3+Ca(NO3)2⟶CaCO3+2NaNO3 how many grams of calcium carbonate, CaCO3, are produced from 79.3 g of sodium car

Alexus [3.1K]

Answer:

74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.

Explanation:

The balanced reaction is:

Na₂CO₃ + Ca(NO₃)₂ ⟶ CaCO₃ + 2 NaNO₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

Na₂CO₃: 1 mole
Ca(NO₃)₂: 1 mole
CaCO₃: 1 mole
NaNO₃: 2 mole

Being the molar mass of the compounds:

Na₂CO₃: 106 g/mole
Ca(NO₃)₂: 164 g/mole
CaCO₃: 100 g/mole
NaNO₃: 85 g/mole

then by stoichiometry the following quantities of mass participate in the reaction:

Na₂CO₃: 1 mole* 106 g/mole= 106 g
Ca(NO₃)₂: 1 mole* 164 g/mole= 164 g
CaCO₃: 1 mole* 100 g/mole= 100 g
NaNO₃: 2 mole* 85 g/mole= 170 g

You can apply the following rule of three: if by stoichiometry 106 grams of Na₂CO₃ produce 100 grams of CaCO₃, 79.3 grams of Na₂CO₃ produce how much mass of CaCO₃?

$mass of CaCO_{3} =\frac{79.3 grams of Na_{2} CO_{3} *100 grams of of CaCO_{3}}{106 grams of Na_{2} CO_{3}}$

mass of CaCO₃= 74.81 grams

<u><em>74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.</em></u>

6 0

3 years ago