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3 years ago

Isotopes are atoms of an element

Chemistry

1 answer:

stellarik [79]3 years ago

6 0

D. With the same number of protons and different number of neutrons.

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Dtermine the volume in liters occupied by 0.030 miles of a gas at stp

aliina [53]

1 mole -------- 22,4 L ( at STP )
0.030 moles --- ?

V = 0.030 * 22,4 / 1

V = 0.672 L

hope this helps!

4 0

4 years ago

Be sure to answer all parts. Write the balanced equations corresponding to the following rate expressions: a) rate = − 1 3 Δ[CH4

Alinara [238K]

Answer : The balanced equations will be:

(a) $3CH_4+2H_2O+CO_2\rightarrow 4CH_3OH$

(b) $2N_2O_5\rightarrow 2N_2+5O_2$

(c) $2H_2+2CO_2+O_2\rightarrow 2H_2CO_3$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

Now we have to determine the balanced equations corresponding to the following rate expressions.

(a) $Rate=-\frac{1}{3}\frac{d[CH_4]}{dt}=-\frac{1}{2}\frac{d[H_2O]}{dt}=-\frac{d[CO_2]}{dt}=+\frac{1}{4}\frac{d[CH_3OH]}{dt}$

The balanced equations will be:

$3CH_4+2H_2O+CO_2\rightarrow 4CH_3OH$

(b) $Rate=-\frac{1}{2}\frac{d[N_2O_5]}{dt}=+\frac{1}{2}\frac{d[N_2]}{dt}=+\frac{1}{5}\frac{d[O_2]}{dt}$

The balanced equations will be:

$2N_2O_5\rightarrow 2N_2+5O_2$

(c) $Rate=-\frac{1}{2}\frac{d[H_2]}{dt}=-\frac{1}{2}\frac{d[CO_2]}{dt}=-\frac{d[O_2]}{dt}=+\frac{1}{2}\frac{d[H_2CO_3]}{dt}$

The balanced equations will be:

$2H_2+2CO_2+O_2\rightarrow 2H_2CO_3$

4 0

3 years ago

Which of the following answers is true for the following statement?

Vsevolod [243]

it is either "aweak acid or a lousy (or very weak) acid"

6 0

3 years ago

how many moles of potassium would you need to prepare 1200 grams of 5.0% potassium sulfate (m/m) solution

Marianna [84]

The moles of potassium that you would need to prepare 1200 g of 5% potassium sulfate solution is 1.538 moles

calculation
calculate the mass potassium using the below formula

%M/M = mass of the solute(potassium)/mass of the solvent (potassium sulfate solution)

let the mass of potassium be represented by Y

then convert % into fraction = 5/100

5/100 = Y/1200
cross multiplication
100y = 6000
divide both side by 100

Y= 60 g

moles of potassium =mass/molar mass

= 60/39=1.538

7 0

4 years ago

Which of the following is the best name for CaF2?

Vladimir79 [104]

Calcium Flouride. It's an ionic bond. Cation + anion with the suffix -ide

8 0

3 years ago

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