I couldn’t really understand the question but i did 4squared + 3r(1) - 7(1)squared and i got -33 + 3r
Answer:
He is hungry.
Step-by-step explanation:
Answer:
<h2>The Possible range for x is : ]8 , 18[</h2>
Step-by-step explanation:
To can draw this triangle if:
4x - (2x - 6) < 42 < 4x + (2x - 6)
solve inequality 1 :
4x - (2x - 6) < 42 ⇔ 2x + 6 < 42 ⇔ 2x < 36 ⇔ x < 18 (1)
Solve inequality 2 :
42 < 4x + (2x - 6) ⇔ 42 < 6x - 6 ⇔ 48 < 6x ⇔ 8 < x (2)
from (1) and (2) we deduce that : 8 < x < 18
Answer:
I need a picture to solve this.
Step-by-step explanation:
Let x=ab=ac, and y=bc, and z=ad.
Since the perimeter of the triangle abc is 36, you have:
Perimeter of abc = 36
ab + ac + bc = 36
x + x + y = 36
(eq. 1) 2x + y = 36
The triangle is isosceles (it has two sides with equal length: ab and ac). The line perpendicular to the third side (bc) from the opposite vertex (a), divides that third side into two equal halves: the point d is the middle point of bc. This is a property of isosceles triangles, which is easily shown by similarity.
Hence, we have that bd = dc = bc/2 = y/2 (remember we called bc = y).
The perimeter of the triangle abd is 30:
Permiter of abd = 30
ab + bd + ad = 30
x + y/2 + z =30
(eq. 2) 2x + y + 2z = 60
So, we have two equations on x, y and z:
(eq.1) 2x + y = 36
(eq.2) 2x + y + 2z = 60
Substitute 2x + y by 36 from (eq.1) in (eq.2):
(eq.2') 36 + 2z = 60
And solve for z:
36 + 2z = 60 => 2z = 60 - 36 => 2z = 24 => z = 12
The measure of ad is 12.
If you prefer a less algebraic reasoning:
- The perimeter of abd is half the perimeter of abc plus the length of ad (since you have "cut" the triangle abc in two halves to obtain the triangle abd).
- Then, ad is the difference between the perimeter of abd and half the perimeter of abc:
ad = 30 - (36/2) = 30 - 18 = 12
