For the scale od the paraboliczne curviczne Ur
Answer / Explanation:
The result of the Training and Exercise Planning Workshop (TEPW) is to set the foundation for the strategy and pattern for a proposed exercise program. The TEPW purpose is to engage elected and selected officials in identifying exercise program priorities and planning a schedule of training and exercise events to meet those priorities.
An essential factor for the exercise management process is to create a collaborative environment where a whole community stakeholders can engage in a forum to discuss and coordinate training and exercise activities across local organizations to maximize the use of available resources and prevent duplication of effort.
Answer:
a) The centripetal acceleration of the car is 0.68 m/s²
b) The force that maintains circular motion is 940.03 N.
c) The minimum coefficient of static friction between the tires and the road is 0.069.
Explanation:
a) The centripetal acceleration of the car can be found using the following equation:

Where:
v: is the velocity of the car = 51.1 km/h
r: is the radius = 2.95x10² m

Hence, the centripetal acceleration of the car is 0.68 m/s².
b) The force that maintains circular motion is the centripetal force:

Where:
m: is the mass of the car
The mass is given by:

Where P is the weight of the car = 13561 N

Now, the centripetal force is:

Then, the force that maintains circular motion is 940.03 N.
c) Since the centripetal force is equal to the coefficient of static friction, this can be calculated as follows:



Therefore, the minimum coefficient of static friction between the tires and the road is 0.069.
I hope it helps you!
Answer:
8.4 kW
Explanation:
Using the Stefan-Boltzmann law,
P = εAσT4
Where:
P: Radiation Energy
ε: Emissivity of the Surface. Check emissivity table below of common materials.
A: Surface Area, in m^2.
σ: Stefan-Boltzmann Constant, σ=5.67 × 10-8 W/m2•K4
T: Temperature
Plugging in values,
P = 0.85 x 3.328 x 5.67 x 10^(-8) x 205
P = 8383 W or 8.4 kW