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2 years ago

A descent vehicle landing on the moon has

Physics

1 answer:

Yakvenalex [24]2 years ago

6 0

The speed of the vehicle is 62.8 m/s

<h3>What is the velocity?</h3>

We have the descent vehicle landing on the moon and the following information are available;

vertical velocity toward the surface of the moon = 29.1 m/s

horizontal velocity = 55.6 m/s

Thus the speed along the descent path = √(29.1)^2 + ( 55.6)^2

= 62.8 m/s

Now the angle is obtained from;

180° - tan-1( 55.6/29.1)

= 118 degrees

Learn more about descent vehicle:brainly.com/question/714514

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The force of gravity depends on the mass of objects and the distance between them. TRUE OR FALSE?

Svet_ta [14]

It is TRUE, Force is proportional to the product of the masses and inversely proportional to the square of the distance between them.

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4 years ago

When you push a child on a swing, your action is most effective when your pushes are timed to coincide with the natural frequenc

OleMash [197]

Answer:

$T = 4.48 s$

we can see that this time period is independent of the mass of the child so answer would be same if the child mass is different

Explanation:

Natural frequency of a simple pendulum of L length is given as

$f = \frac{1}{2\pi}\sqrt{\frac{g}{L}}$

so the time period of the oscillation is given as

$T = 2\pi \sqrt{\frac{L}{g}}$

so we will have

$L = 5 m$

$T = 2\pi\sqrt{\frac{5}{9.81}}$

$T = 4.48 s$

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4 years ago

Two long, straight wires are separated by 0.120 m. The wires carry currents of 11 A in opposite directions, as the drawing indic

rewona [7]

Answer:

The magnitude of the magnetic field is 1.83 x $10^{-5}$ T.

Explanation:

The flow of an electric current in a straight wire induces magnetic field around the wire. When current is flowing through two wires in the same direction, a force of attraction exists between the wires. But if the current flows in opposite directions, the force of repulsion is felt by the wires.

In the given question, the direction of flow of current through the wires is opposite, thus both wires applies the same field on each other. The result to repulsion between them.

The magnetic field (B) between the given wires can be determined by:

B = $\frac{U_{o}I }{2\pi r}$

where: I is the current, r is the distance between the wires and $U_{0}$ is the magnetic field constant.

But, I = 11 A, r = 0.12 m and $U_{0}$ = 4 $\pi$ x $10^{-7}$ Tm/A

So that;

B = $\frac{4\pi *10^{-7}*11 }{2\pi *0.12}$

= 1.8333 x $10^{-5}$

B = 1.83 x $10^{-5}$ T

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3 years ago

Inez uses hairspray on her hair each morning before going to school. The spray spreads out before reaching her hair partly becau

Tamiku [17]

Answer:

$7.0\cdot 10^{-13}C$

Explanation:

The magnitude of the electrostatic force between two charged objects is

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is the separation between the two charges

The force is attractive if the charges have opposite sign and repulsive if the charges have same sign.

In this problem, we have:

$r=0.070 cm =7\cdot 10^{-4} m$ is the distance between the charges

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Re-arranging the equation and solving for q, we find the charge on each drop:

$F=\frac{kq^2}{r^2}\\q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(9.0\cdot 10^{-9})(7\cdot 10^{-4})^2}{8.99\cdot 10^9}}=7.0\cdot 10^{-13}C$

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3 years ago

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Explanation:

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3 years ago