Answer:
A. At the top of the rock stack.
Explanation:
Answer:
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Explanation:
<u>1) Chemical equilibrium</u>
- 2Hg (l) + O₂ (g) ⇄ 2HgO (s) (the double arrow indicates an equilibrium reaction)
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<u>2) Equilibrium constant, Kc:</u>
- The equilibrium constant, Kc, is equal to product of the concentrations of each product,each raised to its stoichiometric coefficient / product of the concentrations of each reactant each raised to its stoichiometric coefficient.
- Since the concentrations of liquid and solid substances remain practically constant, their value is incorporated into the constant Kc, and the equation only uses the concentrations of the aqueous or gaseous substances.
Thus, the equation to use is:
<u>3) Determine the concentration of O₂ (g)</u>
- M = number of moles / volume in liters
- Number of moles = mass in grams / molar mass
- Number of moles of O₂ (g) = 13.4 g / 32.00 g/mol = 0.419 mol
- M = 0.419 mol / 5.2 liter = 0.0806 mol / liter = 0.0806 M
<u>4) Compute Kc</u>
- Kc = 1 / 0.0 806 M = 12.4 M⁻¹ ← answer
Answer:
2Fe + 3CuSO₄ → Fe₂(SO₄)₃ + 3Cu
Explanation:
The reactants are:
Iron = Fe
Copper (II) sulfate solution = CuSO₄
The reaction is given as:
Fe + CuSO₄ → Fe₂(SO₄)₃ + Cu
This is a single displacement reaction;
Now let us balance the equation;
aFe + bCuSO₄ → cFe₂(SO₄)₃ + dCu
Conserving Fe;
a = 2c
Conserving Cu;
b = d
Conserving S;
b = 3c
Conserving O;
4b = 12c
let b = 1;
c =
d = 1
a =
Multiply through by 3 to get whole numbers;
a = 2, b = 3, c = 1 and d = 3
2Fe + 3CuSO₄ → Fe₂(SO₄)₃ + 3Cu
Answer:
The graph of this equation is shown in Figure 1. As you can see this is a straight line with negative slope and does not intersect the y-axis. So the ...
Explanation:
In the galvanic or voltaic cell, the standard cell potential is 1.67 V. The standard potential is the difference between the reduction potential of cathode and anode.
<h3>What is an electrochemical cell?</h3>
An electrochemical cell produces energy by a sponteanous chemical process. A galvanic or voltaic cell produces energy by a sponteanous chemical reaction.
Hence, given the standard reduction potentials;
Sn4+ + 2e- ==> Sn2+ Eº = 0.15 V (anode)
Co3+ + 2e- ==> Co2+ Eº = 1.82 V (cathode)
Eºcell = 1.82 V - 0.15 V = 1.67 V
Learn more about electrochemical cell: brainly.com/question/12034258