Answer:
The rate of transfer of energy is equal to 23.76W or 23.76J/s as may be required both forms are correct. The physical quantities needed to calculate the rate of energy transfer are the linear mass density or mass per unit length, tension force, amplitude, angular frequency( which is equal to 2pi •f )
Explanation:
The required quantity is the average power or average rate of energy transfer which differs from the maximum or instantaneous rate of energy transfer. The calculation steps to the answer above can be found in the attachment below. Should the requested quantity be the instantaneous quantity the answer will be 2 x Pav which equals 47.52W or 47.52J/s.
Answer:
a ) 2.368 rad/s
b) 3.617 rad/s
Explanation:
the minimum angular velocity that Prof. Stefanovic needs to spin the bucket for the water not to fall out can be determined by applying force equation in a circular path
i.e
------ equation (1)
where;


Also

since; that is the initial minimum angular velocity to keep the water in the bucket
Now; we can rewrite our equation as :

So; Given that:
The rope that is attached to the bucket is lm long and his arm is 75 cm long.
we have our radius r = 1 m + 75 cm
= ( 1 + 0.75 ) m
= 1.75 m
g = acceleration due to gravity = 9.81 m/s²
Replacing our values into equation (2) ; we have:

b) if he detaches the rope and spins the bucket by holding it with his hand ; then the radius = 0.75 m
∴

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Answer:
83000000
Explanation:
Conversion factor: 1 kg = 100000 cg
1) Centigram = Kilogram * 100000
2) Centigram = 830 * 100000
3) Centigram = 83000000
~~Hope this helps~~
The rest energy of the proton will be 938 MeV. The rest energy is related to the rest mass of the proton.
<h3>What is rest energy?</h3>
The rest energy is the rest mass times the square of the speed of light of a particle at rest in an inertial frame of reference.
The rest energy is found as;

Convert into the mega electron volt;

Hence, the rest energy of the proton will be 938 MeV
To learn more about the rest energy, refer to the link;
brainly.com/question/15047418
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