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storchak [24]
2 years ago
14

A skateboarder is standing at the top of a tall ramp waiting to begin a trip. The skateboarder has

Physics
2 answers:
son4ous [18]2 years ago
8 0
<span>. An object at an elevated position will have stored energy while not in motion potential energy  is given by  (m*h*g) or
 (weight*h) due to gravity.
so it is
potential energy only
socorrec toption is
B
hope it helps </span>
MrRa [10]2 years ago
5 0

Answer:

Potential energy only

Explanation:

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What does vf stand for<br> a.fringe velocity<br> b.first velocity<br> c.final velocity
Elza [17]
The correct answer is C. Final Velocity

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5 0
2 years ago
How can a karate expert break a concrete block
FinnZ [79.3K]

Many ways, but some of the most famous are kicks (side, back, front, snap) or a smash.

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8 0
3 years ago
a projectile is lunched with an initial speed of 60.0mm/s at an angle of 30.0° above the horizontal.The projectile lands on a hi
alexandr402 [8]

Answer:

52 mm/s (approximately)

Explanation:

Given:

Initial speed of the projectile is, u=60.0\ mm/s

Angle of projection is, \theta=30.0\°

Time taken to land on the hill is, t=4\ s

In a projectile motion, there is acceleration only in the vertical direction which is equal to acceleration due to gravity acting vertically downward. There is no acceleration in the horizontal direction.

So, the velocity in the horizontal direction always remains the same.

The horizontal component of initial velocity is given as:

u_x=u\cos\theta\\u_x=60\times \cos(30)\\u_x=30\sqrt3\approx52\ mm/s

Now, the velocity in the vertical direction goes on decreasing and becomes 0 at the highest point of the trajectory. So, at the highest point, only horizontal component acts.

Therefore, the projectile's velocity at the highest point of its trajectory is equal to the horizontal component of initial velocity and thus is equal to 52 mm/s.

6 0
3 years ago
I’m so confused. please help. i don’t know what i’m suppose to do
aniked [119]

Answer:

Maybe put them in order ????

Explanation:

4 0
3 years ago
A particle on a spring moves in simple harmonic motion along the x axis between turning points at x1 = 95 cm and x2 = 135 cm. (i
uranmaximum [27]

Answer:

(i) x = 115\,cm, (ii) x = 95\,cm, (iii) x = 95\,cm

Explanation:

(i) x_{1} and x_{2} represent the points where particle has a velocity of zero and spring reach maximum deformation, Given the absence of non-conservative force and by the Principle of Energy Conservation, the position where particle is at maximum speed is average of both extreme positions:

x = 115\,cm

(ii) Maximum accelerations is reached at x_{1} and x_{2}.

x = 95\,cm

(iii) Greatest net forces exerted on the particle are reached at  x_{1} and x_{2}.

x = 95\,cm

8 0
2 years ago
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