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alexandr1967 [171]
3 years ago
12

How much dirt is there in a hole 3 feet deep, 6 ft long and 4 ft wide?

Physics
2 answers:
9966 [12]3 years ago
6 0
If its a hole there is no dirt in it?
nikitadnepr [17]3 years ago
5 0
0? It is a hole so there would be no dirt.

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Luke Autbeloe drops a pile of roof shingles from the top of a roof located 8.52
krek1111 [17]

Answer:

t = 1.31 s

Explanation:

Given that,

The top of a roof is located 8.52  meters above the ground.

We need to find the time required for the shingles to reach  the ground. Let the time be t. Its initial velocity was 0 as it was at rest initially. Using the equation of motion to find it as follows :

s=ut+\dfrac{1}{2}gt^2

Where

t is the time and u = 0

s=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2s}{g}} \\\\t=\sqrt{\dfrac{2\times 8.52}{9.8}} \\\\t=1.31\ s

So, it will take 1.31 seconds for the shingles to reach the ground.

5 0
3 years ago
Homework help plz it would help a lot ​
blagie [28]

#82

here we know that

acceleration = 2 m/s/s

time = 5 s

initial speed = 4 m/s

now we can use kinematics to find the final speed

v_f = v_i + at

v_f = 4 + 2(5)

v_f = 14 m/s

So correct answer will be option D)

#83

here we know that

acceleration = 3 m/s/s

time = 4 s

initial speed = 5 m/s

now we can use kinematics to find the final speed

v_f = v_i + at

v_f = 5 + 3(4)

v_f = 17 m/s

So correct answer will be option C)

#84

here we know that

acceleration = 7 m/s/s

time = 3 s

initial speed = 8 m/s

now we can use kinematics to find the final speed

v_f = v_i + at

v_f = 8 + 7(3)

v_f = 29 m/s

So correct answer will be option C)

6 0
3 years ago
which machine changes the direction of force needed to do a task without changing the size of the force needed?
Evgen [1.6K]
<span>A pulley is able to do that.</span>
7 0
4 years ago
Alex is asked to move two boxes of books in contact with each other and resting on a frictionless floor. He decides to move them
Anit [1.1K]

Answer:

2.8 N

Explanation:

Fp = 7.7 N

mA = 12.1 kg

mB = 7 kg

Let a be the acceleration and Fc be the contact force between A and B.

By the free body diagram, use Newton's second law

Fp - Fc = mA x a ..... (1)

Fc = mB x a ..... (2)

Adding both the equations

Fp = (mA + mB) x a

7.7 = (12.1 + 7) x a

a = 0.4 m/s^2

Substitute this value in equation (2), we get

Fc = 7 x 0.4 = 2.8 N

Thus, the contact force between the two blocks is 2.8 N.

Explanation:

3 0
3 years ago
A 1000 kg satellite and a 2000 kg satellite follow exactly the same orbit around the earth. What is the ratio F1/F2 of the gravi
Tamiku [17]

Answer:

the <em>ratio F1/F2 = 1/2</em>

the <em>ratio a1/a2 = 1</em>

Explanation:

The force that both satellites experience is:

F1 = G M_e m1 / r²       and

F2 = G M_e m2 / r²

where

  • m1 is the mass of satellite 1
  • m2 is the mass of satellite 2
  • r is the orbital radius
  • M_e is the mass of Earth

Therefore,

F1/F2 = [G M_e m1 / r²] / [G M_e m2 / r²]

F1/F2 = [G M_e m1 / r²] × [r² / G M_e m2]

F1/F2 = m1/m2

F1/F2 = 1000/2000

<em>F1/F2 = 1/2</em>

The other force that the two satellites experience is the centripetal force. Therefore,

F1c = m1 v² / r    and

F2c = m2 v² / r

where

  • m1 is the mass of satellite 1
  • m2 is the mass of satellite 2
  • v is the orbital velocity
  • r is the orbital velocity

Thus,

a1 = v² / r ⇒ v² = r a1    and

a2 = v² / r ⇒ v² = r a2

Therefore,

F1c = m1 a1 r / r = m1 a1

F2c = m2 a2 r / r = m2 a2

In order for the satellites to stay in orbit, the gravitational force must equal the centripetal force. Thus,

F1 = F1c

G M_e m1 / r² = m1 a1

a1 = G M_e / r²

also

a2 = G M_e / r²

Thus,

a1/a2 = [G M_e / r²] / [G M_e / r²]

<em>a1/a2 = 1</em>

4 0
3 years ago
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