Answer:
t = 1.31 s
Explanation:
Given that,
The top of a roof is located 8.52 meters above the ground.
We need to find the time required for the shingles to reach the ground. Let the time be t. Its initial velocity was 0 as it was at rest initially. Using the equation of motion to find it as follows :

Where
t is the time and u = 0

So, it will take 1.31 seconds for the shingles to reach the ground.
#82
here we know that
acceleration = 2 m/s/s
time = 5 s
initial speed = 4 m/s
now we can use kinematics to find the final speed



So correct answer will be option D)
#83
here we know that
acceleration = 3 m/s/s
time = 4 s
initial speed = 5 m/s
now we can use kinematics to find the final speed



So correct answer will be option C)
#84
here we know that
acceleration = 7 m/s/s
time = 3 s
initial speed = 8 m/s
now we can use kinematics to find the final speed



So correct answer will be option C)
<span>A pulley is able to do that.</span>
Answer:
2.8 N
Explanation:
Fp = 7.7 N
mA = 12.1 kg
mB = 7 kg
Let a be the acceleration and Fc be the contact force between A and B.
By the free body diagram, use Newton's second law
Fp - Fc = mA x a ..... (1)
Fc = mB x a ..... (2)
Adding both the equations
Fp = (mA + mB) x a
7.7 = (12.1 + 7) x a
a = 0.4 m/s^2
Substitute this value in equation (2), we get
Fc = 7 x 0.4 = 2.8 N
Thus, the contact force between the two blocks is 2.8 N.
Explanation:
Answer:
the <em>ratio F1/F2 = 1/2</em>
the <em>ratio a1/a2 = 1</em>
Explanation:
The force that both satellites experience is:
F1 = G M_e m1 / r² and
F2 = G M_e m2 / r²
where
- m1 is the mass of satellite 1
- m2 is the mass of satellite 2
- r is the orbital radius
- M_e is the mass of Earth
Therefore,
F1/F2 = [G M_e m1 / r²] / [G M_e m2 / r²]
F1/F2 = [G M_e m1 / r²] × [r² / G M_e m2]
F1/F2 = m1/m2
F1/F2 = 1000/2000
<em>F1/F2 = 1/2</em>
The other force that the two satellites experience is the centripetal force. Therefore,
F1c = m1 v² / r and
F2c = m2 v² / r
where
- m1 is the mass of satellite 1
- m2 is the mass of satellite 2
- v is the orbital velocity
- r is the orbital velocity
Thus,
a1 = v² / r ⇒ v² = r a1 and
a2 = v² / r ⇒ v² = r a2
Therefore,
F1c = m1 a1 r / r = m1 a1
F2c = m2 a2 r / r = m2 a2
In order for the satellites to stay in orbit, the gravitational force must equal the centripetal force. Thus,
F1 = F1c
G M_e m1 / r² = m1 a1
a1 = G M_e / r²
also
a2 = G M_e / r²
Thus,
a1/a2 = [G M_e / r²] / [G M_e / r²]
<em>a1/a2 = 1</em>