Rocket thrust equation
= ( mass flow rate of fuel burnt ) X (Velocity of gas ejected ) + ( Exit Pressure - Outdoor Pressure ) X ( Area of exhaust )
In this case, we can assume the exit pressure = outdoor pressure and since area of exhaust is not given, it can be assumed to be negligible.
In this case, by Newton 3rd’s law,
Force exerted by gas on rocket
= Force exerted by rocket on gas
= (10kg/s) X (5 x 10^3 m/s)
= 5 x 10^4 N
Answer:
- <u>C = Q/∆V . So the overall strategy here is to find the potential difference ∆V corresponding to a particular Q on an object, then take the ratio.</u>
Explanation:
Capacitance is the amount of charge something can hold for a given ap- plied potential difference between separated parts of the conductor:
Answer:
б / 
Ф ( б / )
Explanation:
<u>Develop a suitable set of dimensionless parameters for this problem</u>
The set of dimensionless parameters for this problem is :
б /
Ф ( б / )
and they are using the pi theorem, MLT systems
attached below is a detailed solution
The answer would be:
Doubling the height will increase the amount of Joules produced.
I think it is when shot scrapes off the top of the turf
