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Aloiza [94]
4 years ago
15

Calculat the acceleration of a person at latitude 40degreesowing to the rotation of the earth.

Physics
1 answer:
beks73 [17]4 years ago
6 0

Answer:

acceleration of person = 9.77 m/s²

Explanation:

given data

latitude = 40 degree

to find out

Calculate the acceleration of a person

solution

we know that here 40 degree = 0.698 rad

so

acceleration of person = g - ω²R    ...............1

and 1 rotation complete in 24 hours = 360 degree

here g is 9.81

so we know Earth angular speed ω = 7.27 × 10^{-5} rad/s and R is earth radius that is 6.37 × 10^{6} m

so

put here value in equation 1 we get

acceleration of person = g - ω²R

acceleration of person = 9.81 - (7.27 × 10^{-5})² × 6.37 × 10^{6}

acceleration of person = 9.77 m/s²

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irina1246 [14]

Answer:

The work done is 360 J.

Explanation:

Given that,

Mass = 50 kg

Distance =3 m

We need to calculate the work done

The work done is equal to the product of force and displacement.

Using formula of work done

W = F\cdot d

W = Fd\cos\theta

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D = distance

θ = Angle between force and displacement

Put the value into the formula

W=120\times3\cos0^{\circ}

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Hence, The work done is 360 J.

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3 years ago
How much work is done if you push a box 150 meters with a force of 1.4 N
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3 years ago
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Leya [2.2K]

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Explanation:

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3 years ago
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6 0
3 years ago
A car starts from rest with an acceleration of 6
mrs_skeptik [129]

Answer:

t=16.67s

Explanation:

From the question, acceleration from 6m/s^2  \ to \ 0m/s^2 in 10 seconds.

Acceleration function can be written as:-

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From the acceleration equation, we can obtain the velocity equation:

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We calculate velocity after 10sec from the above v(t) as 30m/s.

To obtain distance travelled after 10 seconds:-

S=\int\limits^{10}_0 {6t-0.3t^2} \, dt=|3t^2-0.1t^3|   \ *lims(10,0)\\ S=200m

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Total time=10+\frac{200}{30}=16.67s

4 0
4 years ago
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