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Rama09 [41]
2 years ago
12

If the length of a string increases 2 times but the mass of the string remains constant, the new density of the string will equa

l the original density multiplied by what factor?
Chemistry
1 answer:
Genrish500 [490]2 years ago
8 0

If the length of a string increases 2 times but the mass of the string remains constant, the original density  will be multiplied by a factor  mathematically given as

v=1.414 times

<h3>Will the new density of the string equal the original density multiplied by what factor?</h3>

Generally, the equation for the  volume is mathematically given as

v = sqt(TL/m)

Where

density = mass/length

Therefore

v2/v1 = \sqrt{L2/L1}

v2/v1 = \sqrt{2}

In conclusion,v ratio will give us

v=1.414 times

Read more about volume

brainly.com/question/1578538

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Don't just use this question for points-
makvit [3.9K]
I believe it is 3 maybe

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8 0
3 years ago
If 4.168 kJ of heat is added to a calorimeter containing 75.40 g of water, the temperature of the water and the calorimeter incr
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Answer:

The value of  the heat capacity of the Calorimeter  C_c = 54.4 \frac{J}{c}

Explanation:

Given data

Heat added Q = 4.168 KJ = 4168 J

Mass of water m_w = 75.40 gm

Temperature change = ΔT = 35.82 - 24.58 = 11.24 ° c

From the given condition

Q = m_w C_w ΔT + C_c ΔT

Put all the values in above equation we get

4168 = 75.70 × 4.18 × 11.24 +  C_c × 11.24

611.37 =  C_c × 11.24

C_c = 54.4 \frac{J}{c}

This is the value of  the heat capacity of the Calorimeter.

7 0
3 years ago
Please help explain and don't answer if you don't know. thank you
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Answer:

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How many moles of water react with 0.946 mol of nitrogen dioxide
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<span>the answer is
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</span>
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