If the length of a string increases 2 times but the mass of the string remains constant, the new density of the string will equa
1 answer:
If the length of a string increases 2 times but the mass of the string remains constant, the original density will be multiplied by a factor mathematically given as
v=1.414 times
<h3>Will the new density of the string equal the original density multiplied by what factor?</h3>Generally, the equation for the volume is mathematically given as
v = sqt(TL/m)
Where
density = mass/length
Therefore
In conclusion,v ratio will give us
v=1.414 times
Read more about volume
You might be interested in
pH=4.625
The classification of this sample of saliva : acid
<h3>Further explanation</h3>The water equilibrium constant (Kw) is the product of concentration
the ions:
Kw = [H₃O⁺] [OH⁻]
Kw value at 25° C = 10⁻¹⁴
It is known [OH-] = 4.22 x 10⁻¹⁰ M
then the concentration of H₃O⁺:
pH=-log[H₃O⁺]
Saliva⇒acid(pH<7)
<u>Answer:</u> The mass of glucose in final solution is 0.420 grams
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
.........(1)
Initial mass of glucose = 10.5 g
Molar mass of glucose = 180.16 g/mol
Volume of solution = 100 mL
Putting values in equation 1, we get:
To calculate the molarity of the diluted solution, we use the equation:
where,
are the molarity and volume of the concentrated glucose solution
are the molarity and volume of diluted glucose solution
We are given:
Putting values in above equation, we get:
Now, calculating the mass of final glucose solution by using equation 1:
Final molarity of glucose solution = 0.0233 M
Molar mass of glucose = 180.16 g/mol
Volume of solution = 100 mL
Putting values in equation 1, we get:
Hence, the mass of glucose in final solution is 0.420 grams