Answer:
23.6 moles
Explanation:
From the question given above, the following data were obtained:
Mass of air = 3.6 Kg
Mass percentage of O₂ = 21%
Number of mole of O₂ =?
Next, we shall convert 3.6 Kg of air to grams (g). This can be obtained as follow:
1 kg = 1000 g
Therefore,
3.6 Kg = 3.6 Kg × 1000 / 1 kg
3.6 Kg = 3600 g
Next, we shall determine the mass of O₂ in the air. This can be obtained as follow:
Mass of air = 3600 g
Mass percentage of O₂ = 21%
Mass of O₂ =?
Mass of O₂ = 21% × 3600
Mass of O₂ = 21/100 × 3600
Mass of O₂ = 756 g
Finally, we shall determine the number of mole of O₂ in the sample of air. This can be obtained as follow:
Mass of O₂ = 756 g
Molar mass of O₂ = 2 × 16 = 32 g/mol
Number of mole of O₂ =?
Mole = mass /Molar mass
Number of mole of O₂ = 756 / 32
Number of mole of O₂ = 23.6 moles
Thus, the number of mole of O₂ in the
sample of air is 23.6 moles
3.41 is the pH value of a sample that has ten times fewer hydronium ions than an equal volume of a vinegar sample with a pH value of 2.4.
Explanation:
pH of the first sample of acetic acid = 2.4
to know the [H+] concentration in the acetic acid solution, the equation used is:
pH = -log [H+]
[H+] = 
[H+] = 
[H+] = 3.98 X
M
The concentration of H+ ion in first case is 3.98 X
M, the second sample has ten times less hydronium ion so concentration of first case is divided by 10.
3.98 x
M
Now pH of the sample having 10 times fewer ions of acetic acid:
pH = -log [H+]
putting the values in the above equation:
pH = -log [3.98 x
M]
pH = 3.41
If solution has ten times less hydronium ion the pH will change to 3.41.
Answer:
urban heat island
Explanation:
occurs when a city experiences much warmer temperatures than nearby rural areas.
Mark me brainliest.
Considering the ideal gas law, the pressure of the gas sample is 122.18 atm.
<h3>What is an ideal gas</h3>
An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
<h3>Definition of ideal gas law</h3>
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:
P×V = n×R×T
<h3>Pressure of the gas sample</h3>
In this case, you know:
- P= ?
- V= 500 mL= 0.5 L
- n= 2.50 moles
- R= 0.082

- T= 25 °C= 298 K
Replacing in the ideal gas law:
P×0.5 L = 2.50 moles ×0.082
×298 K
Solving:
P= (2.50 moles ×0.082
×298 K)÷ 0.5 L
<u><em>P= 122.18 atm</em></u>
Finally, the pressure of the gas sample is 122.18 atm.
Learn more about the ideal gas law:
brainly.com/question/4147359
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