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Ad libitum [116K]
3 years ago
13

The ability to pound metal into a flat sheet without breaking it is:

Chemistry
2 answers:
lora16 [44]3 years ago
5 0

Answer: B

Explanation: Cuz .

Sauron [17]3 years ago
3 0

Answer: The answer to your question is A

Explanation: Hey I miss you

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The nutrition label on the back of a package of hotdogs (purchased within the US) indicates that one hotdog contains 100 calorie
Olenka [21]

Answer:

C. 100

Explanation:

Biochemical researches and studies have found out that an average health hotdog has a calorie of between 100 and 150 which is usually dependent on the additives.

Since the nutrition label on the back of a package of hotdogs (purchased within the US) indicates that one hotdog contains 100 calories then it truly contains such amount of calories. The standard number of calories present in a hotdog is independent of the amount eaten by individuals.

5 0
3 years ago
A student performs an experiment to determine the molar mass of magnesium oxide. The student repeats the experiment five times a
mestny [16]

Answer:

Percent relative error = 0.191%

Explanation:

Relative error is a measure of accuracy (How closeness is the measure to the accepted value) for a determined data. The formula is:

Percent relative error = |Experimental - Accepted| / Accepted * 100

<em>Where experimental is the average of the data:</em>

(40.220g/mol + 40.654g/mol + 40.314g/mol + 40.165g/mol + 40.554g/mol) / 5 =

40.381g/mol

Replacing using accepted value = 40.304g/mol:

|40.381g/mol - 40.304g/mol| / 40.304g/mol * 100

<h3>Percent relative error = 0.191%</h3>
5 0
3 years ago
When electrons are added to the outer most shell of a carbon atom what does it form
bagirrra123 [75]
When electrons are added to the outermost shell of a carbon atom, it forms an anion.
3 0
3 years ago
Calculate the molality of isoborneol in the product if, a) the melting point of pure camphor is 179°C and the melting point take
tresset_1 [31]

Answer:

The molality of isoborneol in camphor is 0.53 mol/kg.

Explanation:

Melting point of pure camphor= T =179°C

Melting point of sample = T_f = 165°C

Depression in freezing point = \Delta T_f=?

\Delta T_f=T- T_f=179^oC-165^oC=14^oC

Depression in freezing point  is also given by formula:

\Delta T_f=i\times K_f\times m

K_f = The freezing point depression constant

m = molality of the sample

i = van't Hoff factor

We have: K_f = 40°C kg/mol

i = 1 (  organic compounds)

\Delta T_f=14^oC

14^oC=1\times 40^oC kg/mol\times m

m=\frac{14^oC}{1\times 40^oC kg/mol}=0.35 mol/kg

The molality of isoborneol in camphor is 0.53 mol/kg.

8 0
3 years ago
How many grams of salt are in 1 kilogram of seawater with average salinity? quizzlet?
Degger [83]
<span>35 grams The average salinity of seawater is 35 parts per thousand, so multiply the mass of seawater provided by 0.035 and you'll get the amount of salt (mostly sodium chloride) dissolved in it. So 1000 g * 0.035 = 35 g Therefore in 1 kilogram of seawater with average salinity, there is 35 grams of salt.</span>
5 0
3 years ago
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