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sergiy2304 [10]

2 years ago

11

The diagram shows a measuring cylinder containing a liquid,and at thay same measuring cylinder when it is empty . What is the de

nsity of the liquid

1 answer:

KatRina [158]2 years ago

3 0

Answer:

A measuring cylinder contains 30 cm :))

Explanation: Hope this helps !!!!

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What is a key difference between chemical and nuclear reactions? In chemical reactions, new compounds are formed. In nuclear rea

SOVA2 [1]

Answer: Chemical reactions involve electron rearrangements, Nuclear reactions involve changes to the nucleus.

Explanation: What is a key difference between chemical and nuclear reactions? Chemical reactions involve electron rearrangements, Nuclear reactions involve changes to the nucleus.

***If you found my answer helpful, please give me the brainliest, please give a nice rating, and the thanks ( heart icon :) ***

8 0

3 years ago

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Your science teacher gives you three liquids to pour into a jar. After pouring, the liquids layer as seen here. What property of

Blizzard [7]

A. mass
b. color
c. density
d. texture

i believe A

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3 years ago

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9) A bug of mass 0.020 kg is at rest on the edge of a solid cylindrical disk (M = 0.10 kg, R = 0.10 m) rotating in a horizontal

natima [27]

Answer:

a. ω₂ = 14rad/s

b. ∇K.E = 0.014J

c. The bug does not conserve force while moving on the disk (non-conservative force).

Explanation:

Mass of the bug (m) = 0.02kg

Mass of the cylindrical disk (M) = 0.10kg

Radius of the disk (r) = 0.10m

Initial angular velocity ω₁ = 10rad/s

final angular velocity ω₂ = ?

a.

To calculate the new angular velocity, we relate it to the conservation of angular momentum of the system I.e when the bug was at the edge of the disk and when it is located at the centre of the disk.

I = Mr² / 2

I₁ = Mr₂ / 2 + mr²

I₁ = moment of inertia when the bug was at the edge

I₁ = [(0.10 * 0.10²) / 2 ] + (0.02 * 0.1²)

I₁ = 0.0005 + 0.0002

I₁ = 7.0*10⁻⁴kgm²

I₂ = moment of inertia when yhe bug was at the center of the disk.

I₂ = Mr² / 2

I₂ = (0.01 * 0.01²) 2

I₂ = 0.0005kgm²

for conservation of angular momentum,

I₁ω₁ = I₂ω₂

solve for ω₂

ω₂ = (I₁ * ω₁) / I₂

ω₂ = (7.0*10⁻⁴ * 10) / 5.0*10⁻⁴

ω₂ = 14 rad/s

b. the change in kinetic energy of the system is

∇K = K₂ - K₁

∇K = ½I₂*ω₂² - ½I₁*ω₁²

∇K = ½(I₂*ω₂² - I₁ω₁²)

∇K = ½[(5.0*10⁻⁴ * 14²) - (7.0*10⁻⁴ * 10²)]

∇k = ½(0.098 - 0.07)

∇K = ½ * 0.028

∇K = 0.014J

c.

The cause of the decrease and increase in kinetic energy is because the bug uses a non-conservative force. To conserve the mechanical energy of a system, all the forces acting in it must be conservative.

The work W produced by this force brings the difference in kinetic energy of the system

W = K₂ - K₁

6 0

3 years ago

The kinetic energy of an object with a mass of 6.8 kg and a velocity of 5.0 m/s is [BLANK] J. (Report the answer to two signific

dmitriy555 [2]

<h2>Hello!</h2>

The answer is:

The kinetic energy of the object is equal to 85 J.

<h2>Why?</h2>

The kinetic energy involves the speed and the mass of an object in motion. We can calculate the following the work needed to speed an object (kinetic energy) using the equation:

$KineticEnergy=\frac{1}{2}mv^{2}$

Where,

m, is the mas of the object

v, is the speed of the object.

Now, we are given:

$mass=m=6.8kg\\speed=v=5\frac{m}{s}$

So, substituting and calculating the kinetic energy of the object, we have:

$KineticEnergy=\frac{1}{2}*6.8kg*(5\frac{m}{s})^{2}$

$KineticEnergy=\frac{1}{2}*6.8kg*(25\frac{m^{2}}{s^{2}})$

$KineticEnergy=\frac{1}{2}*170kg\frac{m^{2}}{s^{2}}$

$KineticEnergy=85kg\frac{m^{2}}{s^{2}}=85J$

We have that the kinetic energy of the object is equal to 85 J.

Have a nice day!

8 0

3 years ago

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A 4 kg box on the ground has a total of three horizontal forces on it as shown. The acceleration of the box is...

Komok [63]

Answer:

C

Explanation:

I did the math and got c so

4 0

3 years ago