Answer: The height of the fluid rise is 0.01m
Explanation:
Using the equation
h = (2TcosѲ )/rpg
h= height of the fluid rise
diameter of the tube =3mm
radius of the tube= 3/2 =1.5mm=0.0015
T= surface tension = 600mN/m=0.6N/m
Ѳ = contact angle = C
p= density =3.7g/cm3= 3700kg/m3
g= acceleration due to gravity =9.8m/s2
h = ( 2*0.6*0.5)/(0.0015*3700*9.8)
h = 0.6/54.39
h= 0.01m
Therefore,the height of the fluid rise is 0.01m
Answer:
Ro = 7.8 [g/cm³]
Explanation:
According to the principle of Archimedes, the volume of a body immersed in a liquid is equal to the volume displaced by water. That is, in this problem The displacement volume is equal to the new volume minus the original volume.
We now know that density is defined as the relationship between mass and volume.
where:
Ro = density [g/cm³]
m = mass = 78 [g]
Vd = displacement volume [cm³]
Answer:
The heat is 115478.4 J.
Explanation:
Given that,
Mass of water = 0.400 kg
Power = 200 W
Suppose, we determine how much heat must be added to the water to raise its temperature from 20.0°C to 89.0°C?
We need to calculate the heat
Using formula of heat
Where, m = mass of water
c = specific heat
Put the value into the formula
Hence, The heat is 115478.4 J.