Question

diver uses a sonar device to determine the distance to her diving partner. The device sends a sound wave and records the time it takes for the wave to reach the diving partner and return to the device. Suppose the wave travels at a rate of about 4000 feet per second. The wave returns 0.8 second(s) after it was sent. How far away is the diving partner?

Answer 1

Answer:

Assuming the divers are not moving. The diving partner is at 1600 feet.

Explanation:

The sound wave have to  go to the diving partner and return, so its traveling the double of the total distance.

Been X= distance, V= speed, and t= time

$x=v*t$

$WaveTravelDistance=4000*0.8\\\\Distance to the partner=WaveTravelDistance/2\\\\WaveTravelDistance=3200feet\\\\Distance to the partner=1600feet$