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WITCHER [35]
3 years ago
6

diver uses a sonar device to determine the distance to her diving partner. The device sends a sound wave and records the time it

takes for the wave to reach the diving partner and return to the device. Suppose the wave travels at a rate of about 4000 feet per second. The wave returns 0.8 second(s) after it was sent. How far away is the diving partner?
Physics
1 answer:
klio [65]3 years ago
8 0

Answer:

Assuming the divers are not moving. The diving partner is at 1600 feet.

Explanation:

The sound wave have to  go to the diving partner and return, so its traveling the double of the total distance.

Been X= distance, V= speed, and t= time

x=v*t\\

WaveTravelDistance=4000*0.8\\\\Distance to the partner=WaveTravelDistance/2\\\\WaveTravelDistance=3200feet\\\\Distance to the partner=1600feet

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Answer:

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Explanation:

Given that,

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Put the value in to the formula

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