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1 year ago

6

What angle (in degrees) is needed between the direction of polarized light and the axis of a polarizing filter to cut its intens

ity to one-seventh of its initial value

1 answer:

ziro4ka [17]1 year ago

7 0

Answer:

I = I0 cos^2 θ

cos^2 θ = I / I0 = 1/7

cos θ = (1 / 7)^1/2 = .378

θ = 67.8 deg

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