Question

A spring has a spring constant of 100 N/m, and the mass hanging from is is 0.71 kg. What is the period of the spring's motion?

Answer 1

k = spring constant of the spring = 100 N/m

m = mass hanging from the spring = 0.71 kg

T = Time period of the spring's motion = ?

Time period of the oscillations of the mass hanging is given as

T = (2π) √(m/k)

inserting the values in the above equation

T = (2 x 3.14) √(0.71 kg/100 N/m)

T = (6.28) √(0.0071 sec²)

T = (6.28) (0.084) sec

T = 0.53 sec

hence the correct choice is D) 0.53