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MrRa [10]
3 years ago
13

A spring has a spring constant of 100 N/m, and the mass hanging from is is 0.71 kg. What is the period of the spring's motion?

Physics
1 answer:
Anuta_ua [19.1K]3 years ago
6 0

k = spring constant of the spring = 100 N/m

m = mass hanging from the spring = 0.71 kg

T = Time period of the spring's motion = ?

Time period of the oscillations of the mass hanging is given as

T = (2π) √(m/k)

inserting the values in the above equation

T = (2 x 3.14) √(0.71 kg/100 N/m)

T = (6.28) √(0.0071 sec²)

T = (6.28) (0.084) sec

T = 0.53 sec

hence the correct choice is D) 0.53

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<em>Hello, </em>

<h3><u>QUESTION)</u></h3>

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